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Westkost [7]
2 years ago
11

A local supermarket organised two weeks of promotions to boost sales. The average dailly salles before the carmpaign is $10 000,

which becomes $11 000 during the promotion (average over 2 weeks). Which analysis below is not useful for evaluating whether the increase in sales is statistically significant? Check the distribution of sales data. Inspect for possible outliers in sales data. Calculate precision of the prediction Monitor sales for longer period of time.
Mathematics
1 answer:
Grace [21]2 years ago
4 0

Answer:

The analysis that is not useful for evaluating whether the increase in sales is statistically significant is to calculate precision of the prediction.

Step-by-step explanation:

" A sales promotion entails the features via advertising and or a discounted price of a particular product or service"

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A fisherman catches fish according to a Poisson process with rate lambda = 0.6 per hour. The fisherman will keep fishing for two
spayn [35]

Answer:

Step-by-step explanation:

Given that a fisherman catches fish according to a Poisson process with rate lambda = 0.6 per hour.

The fisherman will keep fishing for two hours.

Since he continues till he gets atleast one fish, we can calculate probability as follows:

(a) Find the probability that he stays for more than two hours.

= Prob (x=0) in I two hours and P(X≥1) in 3rd hour

=P(x=0)*P(X=0)*P(X≥1) (since each hour is independent of the other)

= 0.5488^2*(1-0.8781)\\\\=0.2645

(b) Find the probability that the total time he spends fishing is between two and five hours.

Prob that he does not get fish in I two hours * prob he gets fish between 3 and 5 hours

=P(0)^2 *F(1)^3\\=0.5488^2*0.2645^3\\=0.00557

(c) Find the expected number offish that he catches.

Expected value in Geometric distribution = \frac{1-p}{p}, where p = prob of getting 1 fish in one hour

= \frac{0.6}{1-0.6} \\=3

(d) Find the expected total fishing time, given that he has been fishing for four hours.

= Expected fishing time total/expected fishing time for 4 hours

=3/0.6*4

= 1.25 hours

4 0
2 years ago
On Friday, there were x students at the baseball game. On Monday, there were half as many students at the game as there were on
Brut [27]

Number of tickets sold on
Friday = x tickets
Monday = (1/2) x
Wednesday = x - 32

8 0
2 years ago
Read 2 more answers
The combined average weight of an okapi and a llama is 450450450 kilograms. The average weight of 333 llamas is 190190190 kilogr
Kisachek [45]
I'm going to assume that you meant 450kg for the combined weight, 190kg more and 3 Llamas. I'm pretty sure Llamas and Okapis don't weigh 450450450kg (that's 993,073,252 pounds). :)

x= Okapi weight
y= Llama weight

EQUATIONS:
There are 2 equations to be written:

1) 450kg is equal to the weight of one Okapi and one Llama

450kg= x + y

2) The weight of 3 llamas is equal to the weight of one Okapi plus 190kg.

3y=190kg + x


STEP 1:
Solve for one variable in one equation and substitute the answer in the other equation.

450kg= x + y
Subtract y from both sides
450-y =x


STEP 2:
Substitute (450-y) in second equation in place of x to solve for y.

3y=190kg + x
3y=190 + (450-y)
3y=640 -y
add y to both sides

4y=640
divide both sides by 4

y=160kg Llama weight


STEP 3:
Substitute 160kg in either equation to solve for x.

3y=190kg + x
3(160)=190 + x
480=190 + x
Subtract both sides by 190

290= x
x= 290kg Okapi weight


CHECK:
3y=190kg + x
3(160)=190 + 290
480=480

Hope this helps! :)
8 0
2 years ago
In a function, y varies inversely with x. The constant of variation is 4. Which table could represent the function?
Nimfa-mama [501]
The equation will be y=4/x. u can make the table of variables by inserting the values of x in the equation. for suppose here, if x=1 then y=4 , x=2 then y=2 and so on.
5 0
2 years ago
Read 2 more answers
PLEASE HELP!! laboratory tests show that the lives of light bulbs are normally distributed with a mean of 750 hours and a standa
Lunna [17]

Answer:

P = 0.0215 = 2.15%

Step-by-step explanation:

First we need to convert the values of 900 and 975 to standard scores using the equation:

z = \frac{x - \mu}{\sigma}

Where z is the standard value, x is the original value, \mu is the mean and \sigma is the standard deviation. So we have that:

standard value of 900: z = \frac{900 - 750}{75} = 2

standard value of 975: z = \frac{975 - 750}{75} = 3

Now, we just need to look at the standard distribution table (z-table) for the values of z = 2 and z = 3:

z = 2 -> p_2 = 0.9772

z = 3 -> p_3 = 0.9987

We want the interval between 900 and 975 hours, so we need the interval between z = 2 and z = 3, so we just need to subtract their p-values:

P = p_3 - p_2 = 0.9987 - 0.9772 = 0.0215

So the probability is 0.0215 = 2.15%

8 0
2 years ago
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