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KengaRu [80]
2 years ago
14

A hair dryer has a switch that allows it to be used in the US (where the AC voltage is 120 V) and in Europe (where the AC voltag

e is 230 V). It accomplishes this by having two different resistance settings. When the switch is in the "120 V" position, the hair dryer uses a resistance value that allows it to operate at its rated power of 1440 W when connected to 120 V, and when the switch is in the "230 V" setting, the hair dryer uses a resistance that allows it to still operate at its rated power of 1440 W when connected to 230 V. A tourist takes her 1440 W dual voltage hair dryer to Europe but forgets to set the switch to the "230 V" position. When she plugs it into the 230 V receptacle and turns it on, it begins to smoke. What power does the hair dryer consume as a result of this mistake?
Physics
1 answer:
saw5 [17]2 years ago
5 0

Answer:

5290 W

Explanation:

Resistance of the drier in 1440W, 120V setting

= V² / W

= 120 x120 / 1440

= 10 ohm

Resistance of the drier in 1440W, 230V setting

= 230 x 230 / 1440

= 36.736 ohm

Now drier of  1440W, 120V setting

used in 230V

Power used by it

= V² / R

= 230 X 230 / 10

= 5290 W

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Answer;

B. Increased levels of carbon dioxide, a greenhouse gas, leads to increased phytoplankton growth.

Explanation;

-A combination of warm water, high nutrient levels, and adequate sunlight may cause a harmful algae bloom. These blooms may damage aquatic ecosystems by blocking sunlight and depleting oxygen that other organisms need to survive.

-Algae blooms have been increasing globally, and climate change may be playing a role in the increment. For instance, during the warm summer season or when water is warmer, some harmful types of algae to grow faster than other, more benign varieties.

-Additionally, the warmer surface water also prevents water from mixing vertically, allowing algae to grow thicker and faster.

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2 years ago
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A projectile follows a straight-line path instead of a parabolic trajectory. Which could be the launch angle? would it be 90 or
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<em>projectile can only follow the straight line path when it is launched upward straightly so the correct option is <u>90 degree with respect to horizontal x -axis ..:)</u></em>
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2 years ago
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If Katie swims from one end of the pool, to the other side, and then swims back to her original spot, her average velocity is ha
Crank

Answer:

false.

Explanation:

Ok, we define average velocity as the sum of the initial and final velocity divided by two.

Remember that the velocity is a vector, so it has a direction.

Then when she goes from the 1st end to the other, the velocity is positive

When she goes back, the velocity is negative

if both cases the magnitude of the velocity, the speed, is the same, then the average velocity is:

AV = (V + (-V))/2  = 0

While the average speed is the quotient between the total distance traveled (twice the length of the pool) and the time it took to travel it.

So we already can see that the average velocity will not be equal to half of the average speed.

The statement is false

4 0
2 years ago
A 1.0 kg object moving at 4.5 m/s has a wavelength of:
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By wave particle  duality.

Wavelength , λ = h / mv

where h = Planck's constant = 6.63 * 10⁻³⁴ Js,  m = mass in kg,  v = velocity in m/s.
m = 1kg,  v = 4.5 m/s

λ = h / mv

λ = (6.63 * 10⁻³⁴) /(1*4.5)

λ ≈  1.473 * 10⁻³⁴  m

Option D.
7 0
2 years ago
A proton of mass mp is released from rest just above the lower plate and reaches the top plate with speed vp. An electron of mas
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Answer:

v_e=\sqrt{\frac{m_pv_p^2}{m_e}}

Explanation:

You can consider that the force that acts over the proton is the same to the force over the electron. This is because the electric force is given by:

F=qE

F_p=F_e

where E is the constant electric field between the parallel plates, and is the same for both electron and proton. Also, the charge is the same.

by using the Newton second law for the proton, and by using kinematic equation for the calculation of the acceleration you can obtain:

m_pa_p=qE\\\\a_p=\frac{v_p^2}{2d}\\\\\frac{m_pv_p^2}{2d}=qE

(it has been used that vp^2 = v_o^2+2ad) where d is the separation of the plates, ap the acceleration of the proton, vp its velocity and mp its mass.

By doing the same for the electron you obtain:

\frac{m_ev_e^2}{2d}=qE

we can equals these expressions for both proton and electron, because the forces qE are the same:

\frac{m_pv_p^2}{2d}=\frac{m_ev_e^2}{2d}\\\\v_e=\sqrt{\frac{m_pv_p^2}{m_e}}

4 0
2 years ago
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