Question

For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser pointer (λ=680nm) through the slit onto a screen 5.4 m away, a diffraction pattern appears. The bright band in the center of the pattern is 7.9 cm wide. What is the width of slide?

Answer 1

Answer:

The width of slide is 0.092 mm.

Explanation:

Given that,

Wave length = 680 nm

Distance between slit and screen D= 5.4 m

Distance of bright band 2y = 7.9 cm

$y =\dfrac{7.9}{2}$

$y=3.95\ cm$

We need to calculate the width of slide

Using formula of width

$d=\dfrac{\lambda D}{y}$

Where, d = width

D =Distance between slit and screen

y = Distance of bright band

Put the value into the formula

$d=\dfrac{680\times10^{-9}\times5.4}{3.95\times10^{-2}}$

$d=0.092\times10^{-3}\ m$

$d=0.092\ mm$

Hence, The width of slide is 0.092 mm.