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aleksklad [387]
2 years ago
8

Several 4-conductor cables are installed in a ladder cable tray without a cover and without exceeding the cable tray fill limit.

Each 4-conductor cable comprises four 1/0 AWG THHN copper conductors, each of which is considered current-carrying. What is the allowable ampacity of each 1/0 AWG THHN copper conductor?
Physics
1 answer:
8090 [49]2 years ago
6 0

Answer: The allowable ampacity is 136 amperes

Explanation:According to the National Electrical Code the ampacity for insulated conductors of type 1/0 AWG THHN is 170 amperes(from tables) for cables no exceeding 3

But we are presented with 4 cables in a tray,

Going by the National Electrical Code where conductors exceeds 3, the allowable ampacity shall be reduced to 80% the of the ampacity gotten from table.

Hence the allowable ampacity for 4 copper cables of type 1/0 AWG THHN is (80/100) *170=136 Amperes

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A steel plate shine but wooden vessel desnt
Tcecarenko [31]

<u>Answer</u> :

A new steel plate shines but an wooden vessel does not shine because new steel plate has lustre. ... Because steel absorbs very little amount of light and reflects back the light but in case of wooden vessel it has dull appearence and reflects very little amount of light so it does not shine.

Please mark as brainliest. . . ☺

4 0
2 years ago
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Odległość między kolejnymi grzbietami fal na morzu wynosi 20 m. Łódź opada z grzbietu fali, unosi się i osiąga ponownie najwyższ
Veronika [31]

Answer:

Explanation:

The distance between successive wave crests at sea is 20 m. The boat descends from the crest of the wave, rises and reaches the highest position again within 5 s. Calculate the wave propagation speed.

Given that,

The distance between two successive crest is 20m

Wavelength is the distance between two successive crest or trough

Then, it's wavelength is λ = 20m

The time to reached the maximum height is 5seconds, then it will take (5×4) to complete one period

Then,

Period T = 20seconds

From wave equation

v = fλ

Where

v is speed

f is frequency and

λ is wavelength

The frequency is related to the period

f =  1 / T

Then,

v = λ / T

So, v = 20 / 20

v = 1 m/s

The speed of propagation of the wave is 1m/s

To Polish

Jeśli się uwzględni,

Odległość między dwoma kolejnymi grzebieniami wynosi 20 m

Długość fali to odległość między dwoma kolejnymi grzebieniami lub dolinami

Zatem jego długość fali wynosi λ = 20 m

Czas do osiągnięcia maksymalnej wysokości wynosi 5 sekund, a następnie ukończenie jednego okresu zajmie (5 × 4)

Następnie,

Okres T = 20 sekund

Z równania falowego

v = fλ

Gdzie

v to prędkość

f oznacza częstotliwość, a

λ jest długością fali

Częstotliwość jest związana z okresem

f = 1 / T

Następnie,

v = λ / T

Zatem v = 20/20

v = 1 m / s

Prędkość propagacji fali wynosi 1m/s

6 0
2 years ago
A Labrador retriever breeder needs to determine if three male pups who were born to Sadie, his black Labrador retriever, are the
Novosadov [1.4K]

Answer: The things we know are:

Sadie, the mother, is a black labrador.

Sam, the possible father, is a yellow labrador.

Discarding things such as a scientific indagation, the breeder could look for traits in the pups.

For example, yellow is recessive against black, so if the pups are yellow, there is probable that the father is Sam, none the less, if the pups are black there is also the possibility where Sam is the father, just in this case the color genes that the pups received are the ones of the mother.

A good starting point is looking at the color, the posture, and things like that.

In the end, these things are only statistics, there is not any determination here, the only real (scientific) determinative process is a paternity test.

7 0
2 years ago
Water is contained in a closed, rigid 0.2 m 3 tank at an initial pressure of 5 bar and a quality of 50%. Heat transfer occurs un
elena55 [62]

Answer:

Final mass=0.89kg

Final pressure=5.6bar

Explanation:

To find mass,m=v/v1

But v1=vf + x(vg-vf)

Vf= 0.001093m^3/kg

Vg= 0.3748m^3/kg

V1= 0.001093+0.5(0.3748-0.001093)

V1= 0.225m^3/kg

M= 0.20/0.225 =0.89kg

Final pressure will be:

V/V1= P/P1

Cross multiply

VP1=V1P

P1= 0.225×5/0.2

P1=:5.6 bar

7 0
2 years ago
If period of the pendulum in preceding sample problem were 24s how tall would the tower be ?
frutty [35]

Answer:

So length of pendulum is 143.129 m

Explanation:

We have given period of simple pendulum is 2 sec

We have to find the length of simple pendulum

Let the length of pendulum is l

Acceleration due to gravityg=9.8m/sec^2 is

Time period is given by T=2\pi \sqrt{\frac{l}{g}}

So 24=2\times 3.14\times  \sqrt{\frac{l}{9.8}}

\sqrt{\frac{l}{9.8}}=3.821

Squaring both side

{\frac{l}{9.8}}=14.60

l =143.129 m

So length of pendulum is 143.129 m

8 0
2 years ago
Read 2 more answers
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