The drive wheel of an engine is 13 inches in diameter, and the pulley on the rotary pump is 5 inches in diameter. If the shafts
of the drive wheel and the pulley are 2 feet apart, what length of belt is required to join them?
1 answer:
Answer: 23.66 in
Explanation:
Drive wheel of engine is larger than pulley of rotary pump
Drive wheel diameter = 13 in
Since radius = diameter / 2
drive wheel radius = 6.5 in
Pulley diameter = 5in
Pulley radius = 2.5 in
Horizontal Distance between pulleys = 2ft
Note : 1 foot = 12 inches
Converting distance to inches ;
Horizontal Distance between pulleys = 2×12 = 24 inches
Difference in height of pulleys = radius 1st pulley - radius of second pulley ;
Height difference = 6.5 - 2.5 = 4 in
From the diagram attached ;
AB = sqrt(BC^2 - AC^2)
Length of belt (AB) = sqrt( 24^2 - 4^2)
Length of belt = sqrt(576 - 16)
Length of belt = sqrt(560)
Length of belt = 23.66 in
You might be interested in
Answer:
The answer is below
Explanation:
Given that:
mass (m) = 86 kg, distance (L) = 2.75 m, θ = 31°, force (F) = 595 N, initial velocity () = 2.4 m/s, g = acceleration due to gravity = 9.8 m/s²
The net work can be gotten from the equation:
From the work-energy theorem equation, we can get her speed at the top of the ramp ()
Hence:
Answer:
$ 18.75
Explanation:
given,
capacity of the Dave’s car = 12 gallons
Assuming that the tank is 3/8 full before
Cost of gas per gallon = $2.50 per gallon of gas
Volume Dave have to fill
=
= of full tank
=
volume Dave have to fill = 7.5 gallons
total money Dave spent
= 7.5 gallons x $2.50
= $ 18.75
Dave have to spend $ 18.75 to fill tank to it capacity.