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2 years ago

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Equilibrium: A 10.0-kg picture is held in place by two wires, the first one hanging at 50.0° to the left of the vertical and the

second one at 45.0° to the right of the vertical. What is the tension in the first wire?

1 answer:

Sonja [21]2 years ago

6 0

Answer:

The tension in the first wire is 70.24N and the tension in the second wire is 75.36N

Explanation:

Check attachment for solution

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The largest single publication in the world is the 1112-volume set of British Parliamentary Papers for 1968 through 1972. The co

Marat540 [252]

Answer:

$m_l=550\ kg$ is the mass of librarian.

Explanation:

Given:

mass of the system, $m_s=3.3\times 10^{3}\ kg$

velocity of librarian relative to the ground, $v_l=2.5\ m.s^{-1}$

velocity of the cart relative to the ground, $v_c=0.5\ m.s^{-1}$

N<u>ow using the principle of elastic collision:</u>

Net momentum of the system is zero.

$m_l\times v_l=(3300-m_l)\times v_c$

$m_l\times 2.5=(3300-m_l)\times 0.5$

$m_l=550\ kg$ is the mass of librarian.

6 0

2 years ago

Read 2 more answers

You and your friend throw balloons filled with water from the roof of a several story apartment house. You simply drop a balloon

Aleks [24]

Answer:

Height = 53.361 m

Explanation:

There are two balloons being thrown down, one with initial speed (u1) = 0 and the other with initial speed (u2) = 43.12

From the given information we make the following summary

$u_{1}$ = 0m/s

$t_{1}$ = t

$u_{2}$ = 43.12m/s

$t_{2}$ = (t-2.2)s

The distance by the first balloon is

$D = u_{1} t_{1} + \frac{1}{2} at_{1}^2$

where

a = 9.8m/s2

Inputting the values

$D = (0)t + \frac{1}{2} (9.8)t^2\\ D = 4.9t^2$

The distance traveled by the second balloon

$D = u_{2} t_{2} + \frac{1}{2} at_{2}^2$

Inputting the values

$D = (43.12)(t-2.2) + \frac{1}{2} (9.8)(t-2.2)^2$

simplifying

$D = 4.9t^2 + 21.56t -71.148$

Substituting D of the first balloon into the D of the second balloon and solving

$4.9t^2 = 4.9t^2 + 21.56t -71.148 \\ 21.56t = 71.148\\ t = 3.3s$

Now we know the value of t. We input this into the equation of the first balloon the to get height of the apartment

$D = 4.9(3.3)^2\\ D = 53.361 m$

7 0

2 years ago

A tennis ball bounces on the floor three times. If each time it loses 22.0% of its energy due to heating, how high does it rise

lesya692 [45]

Answer:

H = 109.14 cm

Explanation:

given,

Assume ,

Total energy be equal to 1 unit

Balance of energy after first collision = 0.78 x 1 unit

= 0.78 unit

Balance after second collision = 0.78 ^2 unit

= 0.6084 unit

Balance after third collision = 0.78 ^3 unit

= 0.475 unit

height achieved by the third collision will be equal to energy remained

H be the height achieved after 3 collision

0.475 ( m g h) = m g H

H = 0.475 x h

H = 0.475 x 2.3 m

H = 1.0914 m

H = 109.14 cm

6 0

2 years ago

A pendulum is made of a small sphere of mass 0.250 kg attached to a lightweight string 1.20 m in length. As the pendulum swings

forsale [732]

Answer:v=2 m/s

Explanation:

Given

Length of string L=1.2 m

mass of pendulum m=0.25 kg

maximum inclination with vertical \theta =34

vertical Rise of Pendulum from its mean position is given by

$\Delta h=L(1-\cos \theta )$

Conserving Energy at top and bottom point

Potential Energy of sphere is converted into kinetic energy of sphere

$mgL(1-\cos \theta )=\frac{mv^2}{2}$

$v=\sqrt{2gL(1-\cos \theta )}$

$v=\sqrt{2\times 9.8\times 1.2(1-\cos 34)}$

$v=\sqrt{4.021}$

$v=2 m/s$

5 0

2 years ago

An electric toaster is rated 1200 watts at 120 volts. what is the total electrical energy used to operate the toaster for 30 sec

Anarel [89]

Energy is calculated as power*time, so give the wattage of 1200 W (equivalent to 1200 Joules/second) and time of 30 seconds, multiplying these gives 36000 J or 36 kJ of electrical energy.

If electrical charge or current is needed: Power = voltage * current, so given the power of 1200 watts and voltage of 120 V, current is 1200 W / 120 V = 10 Amperes. Charge is calculated by multiplying 10 A*30 s = 300 C.

3 0

2 years ago