Addition of water to an alkyne gives a keto-enol tautomer product. draw an enol that is in equilibrium with the given ketone.

1 answer:

8 0

If water were added to an alkyne and the product was 2-pentanone, then the alkyne must have been 1-pentyne. 2-pentyne would have given a mixture of 2- and 3-pentanone.

<span>The enol that would give 2-pentanone would have been pent-1-en-2-ol. Because an equilibrium favors the ketone so greatly, equilibrium is not a good description. If the ketone were treated with bromine, little reaction would be seen as the enol content would be too low. If a catalyst were added, NaOH for example, then formation of the enolate of pent-1-en-2-ol would form and react with bromine. This would eventually give a bromoform product. Under acidic conditions, the enol would favor formation of the more substituted enol consistent with alkene stability.</span>

You might be interested in

Explain why the actual electron configurations of 2-7-1-1 represents a sodium in an excited state

andre [41]

The second shell is left at 7, it should be filled to 8 to go to the next shell.

8 0

1 year ago

Which family on the periodic table is least likely to enter into chemical reactions? 1 2 17 18

vekshin1

Elements present in group 18 are known as noble gases. The outermost shell of these elements are completely filled.

18 is the answer

6 0

1 year ago

Read 2 more answers

NO2 can react with the NO in smog, forming a bond between the N atoms. Draw the structure of the resulting compound, including f

ELEN [110]

First, let's write down the balanced chemical reaction between the given reactants:

NO₂ + NO → N₂O + O₂

The Lewis structure of the main product is shown in the attached picture. To determine the formal charge of each element, the formula is as follows:

Formal Charge = Valence electrons - Non-bonding valence electrons - (Bonding electrons/2)

For the leftmost N:
Formal charge = 5 - 2 - 6/2 = 0
For the middle N:
Formal charge = 5 - 0 - 8/2 = 1
For O:
Formal charge = 6 - 6 - 2/2 = -1

6 0

1 year ago

A double-replacement reaction takes place when aqueous k2so4 reacts with aqueous pb(no3)2. you would expect the products of this

SpyIntel [72]

A double replacement is when the reactants switch with their opposite charge. For example, AB + CD = AD + BC.

In this case the given is K2SO4 + Pb(NO3)2 = ____ + ____

The answers is PbSO4 and KNO3 would expect the products of this reaction.

8 0

1 year ago

Read 2 more answers

A 0.271 g sample of an unknown vapor occupies 294 ml at 140.°c and 847 mmhg. the empirical formula of the compound is ch2. what

sdas [7]

When the molar mass M = mass (g)/ no.of moles (Mol)

∴ moles= 0.271 g / M

By using the gas equation:

PV = n RT

when P is the pressure = 847 mmHg / 760 = 1.11 atm

V is the volume = 0.294 L

n = 0.271 / M

R is constant = 0.0821

T= 140+273 = 413 K

so by substitution:

when n = PV/RT

∴ 0.271/ M = 1.11 atm *0.294 L/ 0.0821 *413

∴ M = 28

when the empirical formula of CH2 = 12+2 = 14

∴ the exact no.of moles = 28/14 = 2

∴the molecular formula = 2(CH2) = C2H4

6 0

1 year ago