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Alchen [17]
2 years ago
10

Lead iodide is virtually insoluble in water so that the reaction appears to go to completion. How many milliliters of 3.550 M HI

(aq) must be added to a solution containing 0.700 mol of to completely precipitate the lead?

Chemistry
2 answers:
Minchanka [31]2 years ago
8 0

Answer:

394mL

Explanation:

the molecular equation is

Pb(NO3)2 + 2 HI = PbI2 + 2 HNO3

the ratio between Pb(NO3)2 and HI is 1 : 2

moles HI required = 0.700 x 2 = 1.40

volume HI = 1.40 mol / 3.550 mol/L=0.394 L = 394 mL

Bad White [126]2 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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In science class, Blaine’s teacher puts one glow stick in a cup of hot water and another glow stick in a cup of cold water. She
timofeeve [1]

Answer:

The glow stick in hot water will be brighter

Explanation:

The glow stick in hot water will be brighter than the glow stick in cold water because the heat from the hot water will cause the molecules in the glow stick to move faster. The faster the molecules move in the glow stick, the sooner and brighter the reaction will be. The cold water will cause molecules to move slowly and it will take longer for the reaction to occur, which will also make it less bright.

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2 years ago
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A sample of element X contains 90% X-35 atoms, 8.0% X-37 atoms, and 2.0% X-38 atoms. The average atomic mass will be closest to
Ne4ueva [31]

To find average atomic mass you multiply the mass of each isotope by its percentage, and then add the values up.

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2 years ago
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How many moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in H2O?
saw5 [17]
The   number  of  moles  of  NaOh that  are    contained  in  65ml  of   2.20M  solution  NaOh  in H2o  is  calculated  using  the  below  formula


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Write down the dissolution equation for rubidium chromate dissolving in water. (Chromate is a polyatomic ion with the formula Cr
ycow [4]

Answer:

Four moles of the cation

Explanation:

2Rb2CrO4(s)<--------> 4Rb^+(aq) + 2CrO4^2-(aq)

Now looking at the reaction equation, it can be seen that one mole of rubidium chromate contains two moles of rubidium ions and one mole of chromate ions.

The dissolution of two moles of rubidium chromate should then yield four moles of rubidium ions and two moles of chromate ions since the ratio of ions present is 2:1.

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5 0
2 years ago
How many grams of nano3 would you add to 500g of h2o in order to prepare a solution that is 0.500 molal in nano3?
VARVARA [1.3K]
When the concentration is expressed in molality, it is expressed in moles of solute per kilogram of solvent. Since we are given the mass of the solvent, which is water, we can compute for the moles of solute NaNO3.

0.5 m = x mol NaNO3/0.5 kg water
x = 0.25 mol NaNO3

Since the molar mass of NaNO3 is 85 g/mol, the mass is

0.25 mol * 85 g/mol = 21.25 grams NaNO3 needed
4 0
2 years ago
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