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Ivenika [448]
2 years ago
6

The gravitational force between the Sun (mass = 1.99 × 1030 kg) and Mercury (mass = 3.30 × 1023 kg) is 8.99 × 1021 N. How far is

Mercury from the Sun?
Physics
2 answers:
Svet_ta [14]2 years ago
8 0
The answer is B - 6.98 x 10^7 km
STALIN [3.7K]2 years ago
4 0

Answer : Distance, d=6.98 × 10⁷ Km

Explanation :

Given that,

Mass of the sun, m₁ = 1.99 × 10³⁰ kg

Mass of Mercury, m₂ = 3.30 × 10²³ kg

Gravitational force between the sun and mercury, F = 8.99 × 10²¹ N

According to Universal law of gravitation,

F=G\dfrac{m_1m_2}{d^2}

d is the distance of mercury from the sun

d=\sqrt{\dfrac{Gm_1m_2}{F}}

d=\sqrt{\dfrac{6.67\times 10^{-11}\times 1.99\times {30}\times 3.30\times 10^{23}}{8.99\times 10^{21}}}

d=\sqrt{4.87\times 10^{21}} m

d=6.98\times 10^{10}\ m

or

d=6.98\times 10^{7}\ Km

So, mercury is 6.98\times 10^{7}\ Km far from the sun.

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Summary:
a= 12.0 m/(s^2)
v= 100m/s
t1= 2.0s => s1=?
t2=5.0s => s2=?
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——————
Solution:
• when t1=2.0 s, I have gone:
S1= v*t1 + 1/2*a*(t1^2)
=100.0 *2 + 1/2*12.0*(2.0^2)
=224 (m)

• when t2=5.0s, I have gone
S2=v*t2+ 1/2*a*(t2^2)
= 100*5.0+ 1/2*12.0*(5.0^2)
=650 (m)

•when t3= 10.0s, I have gone:
S3=v*t3+ 1/2*a*(t3^2)
=100*10.0+ 1/2*12*(10.0^2)
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2 years ago
Recall the previous question and the scenario with Zamir and Talia finding their way through a maze. Why is their displacement t
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A 4.00-kg mass is attached to a very light ideal spring hanging vertically and hangs at rest in the equilibrium position. The sp
Ahat [919]

Answer:

|v| = 8.7 cm/s

Explanation:

given:

mass m = 4 kg

spring constant k = 1 N/cm = 100 N/m

at time t = 0:

amplitude A = 0.02m

unknown: velocity v at position y = 0.01 m

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-0.02 = 0.02cos(0 + \phi) => \phi = \pi

2. Finding time t at position y = 1 cm:

0.01 =0.02cos(\omega t + \pi)\\ \frac{1}{2}=cos(\omega t + \pi)\\t=(acos(\frac{1}{2})-\pi)\frac{1}{\omega}

3. Find velocity v at time t from equation 2:

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We can use the following SUVAT equation to solve the problem:

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Solving the equation for a, we find the acceleration:

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We have energy E = hc/λ, where h is Planck's constant c is speed of light and λ is the wavelength.

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Energy of one mol = 3.73*10^{-19}*6.023*10^{23}=225 kJ/mol

Energy of one mol of photons generated from this device = 225 kJ

3 0
2 years ago
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