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insens350 [35]
2 years ago
13

Given: m∠AEB = 45° ∠AEC is a right angle. Prove: Ray E B bisects ∠AEC. 3 lines extend from point E. A horizontal line extends to

the left to point A and a vertical line extends up to point C. Another line extends halfway between the other 2 lines to point B. Lines A E and E C form a right angle. Proof: We are given that m∠AEB = 45° and ∠AEC is a right angle. The measure of ∠AEC is 90° by the definition of a right angle. Applying the gives m∠AEB + m∠BEC = m∠AEC. Applying the substitution property gives 45° + m∠BEC = 90°. The subtraction property can be used to find m∠BEC = 45°, so ∠BEC ≅ ∠AEB because they have the same measure. Since Ray E B divides ∠AEC into two congruent angles, it is the angle bisector.
Mathematics
2 answers:
Marta_Voda [28]2 years ago
3 0

Answer:

RIGHT Angle Addition Postulate.

Step-by-step explanation:

Applying the RIGHT Angle Addition Postulate gives m∠AEB + m∠BEC = m∠AEC. Applying the substitution property gives 45° + m∠BEC = 90°. The subtraction property can be used to find m∠BEC = 45°, so ∠BEC ≅ ∠AEB because they have the same measure. Since Ray E B divides ∠AEC into two congruent angles, it is the angle bisector.

balu736 [363]2 years ago
3 0

Answer:

The question is not complete though.

It is the right angle addition postukate.

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