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DaniilM [7]
2 years ago
10

A particle of mass 5kg is pulled along a rough horizontal surface by a string which is inclined at 60° to the horizontal. if the

acceleration of the particle is 1/3×g ms^-2 and the coefficient of friction between the particle and the plane is 2/3, find the tension in the string.​
Physics
1 answer:
guajiro [1.7K]2 years ago
7 0

Answer:

Explanation:

20 because i said

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Which of the following forms of radiation can penetrate up to a 2-cm layer of skin tissue?
Dmitry_Shevchenko [17]

Answer:

d). X-rays

Explanation:

X -rays are also called photons. They are a packet of electro magnetic radiation. X rays originate from the shell of the electron.  X rays are highly penetrating, and have a shorter wavelength than alpha particles and the beta particles. They are similar to the gamma rays which are also has a high penetrating power and easily pass through the human body.

 Thus X rays can penetrate a skin tissue upto 2 cm thickness.

4 0
2 years ago
Read 2 more answers
The center of a long frictionless rod is pivoted at the origin and the rod is forced to rotate at a constant angular velocity Q
Doss [256]

Answer:

The answers can be found attached.

7 0
2 years ago
If period of the pendulum in preceding sample problem were 24s how tall would the tower be ?
frutty [35]

Answer:

So length of pendulum is 143.129 m

Explanation:

We have given period of simple pendulum is 2 sec

We have to find the length of simple pendulum

Let the length of pendulum is l

Acceleration due to gravityg=9.8m/sec^2 is

Time period is given by T=2\pi \sqrt{\frac{l}{g}}

So 24=2\times 3.14\times  \sqrt{\frac{l}{9.8}}

\sqrt{\frac{l}{9.8}}=3.821

Squaring both side

{\frac{l}{9.8}}=14.60

l =143.129 m

So length of pendulum is 143.129 m

8 0
2 years ago
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An airplane is delivering food to a small island. It flies 100 m above the ground at a speed of 150 m/s .
miss Akunina [59]

Answer:

The airplane should release the parcel 6.7*10^2 m before reaching the island

Explanation:

The height of the plane is y_0=100m, and its speed is v=150 m/s

When an object moves horizontally in free air (no friction), the equation for the y measured with respect to ground is

y=y_0 - \frac{gt^2}{2}    [1]

And the distance X is

x = V.t     [2]

Being t the time elapsed since the release of the parcel

If we isolate t from the equation [1] and replace it in equation [2] we get

X = V . \sqrt{\frac{2y_0}{g}}

Using the given values:

x = 150 m/s  \sqrt{\frac{2\times 100m}{9.8 m/sec^2}}

x = 6.7*10^2 m

4 0
2 years ago
A sample of silver (with work function Φ=4.52 eV ) is exposed to an ultraviolet light source (????=200 nm), which results in the
Crank

Answer:

1. c

2. e

3. d

Explanation:

1.

From Einstein's Photoelectric Equation, we know that:

Energy given up by photon = Work Function + K.E of Electron

hc/λ = φ + K.E

where,

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of light source = 200 nm = 2 x 10⁻⁷ m

φ = (5.1 eV)(1.6 x 10⁻¹⁹ J/eV) = 8.16 x 10⁻¹⁹ J

Therefore,

(6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(2 x 10⁻⁷ m) - 8.16 x 10⁻¹⁹ = K.E

K.E = (9.939 - 8.16) x 10⁻¹⁹ J

K.E = 1.778 x 10⁻¹⁹ J

The positive answer shows that electrons will be emitted. Since it is clear from the equation the the K.E of electron decreases with the increase in work function. Therefore:

c. <u>less energetic photo-electrons (on average)</u>

<u></u>

2.

The increase in light sources means an increase in the intensity of light. The no. of photons are increased, due to increase of intensity. Thus, more photons hit the metal and they eject greater no. of electrons. Therefore,

e. <u>more photo-electrons ejected</u>

<u></u>

3.

X-rays have smaller wavelength and greater energy than ultraviolet rays. Thus, the photons with greater energy will strike the metal and as a result, electrons with higher energy will be ejected.

d. <u>more energetic photo-electrons (on average)</u>

8 0
2 years ago
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