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Nikolay [14]
2 years ago
4

Calculate the freezing point of a solution containing 6.50g of benzene in 160g of chloroform

Chemistry
1 answer:
Aleonysh [2.5K]2 years ago
5 0

Answer:

Freezing point of the solution will be -65.9°C

Explanation:

The addition of a solute to a solvent decreases freezing point of pure solvent. Freezing point depression formula is:

ΔT = K×m

Where ΔT is change in freezing point (-63.5°C is freezing point of pure chloroform), K is solvent constant (4.68°Ckg/mol for chloroform) and m is molality (moles of solute per kg of solvent).

Moles of benzene are:

6.50g × (1mol / 78.11g) = 0.0832 moles of benzene

0.0832 mol / 0.160kg = 0.52 mol/kg of solution.

Replacing these values in the formula:

(-63.5 - X)°C   = 4.68°Ckg/mol× 0.52 mol /kg

X = -65.9°C

<em>Freezing point of the solution will be -65.9°C</em>

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There are ________ hydrogen atoms in 25 molecules of c4h4s2.
coldgirl [10]

Answer: 100.


Explanation:


1) The subscripts to the right of each element (symbol) in the chemical formula tells the number of atoms of that element present in one unit formula.


2) The unit formula of C₄H₄S₂ is equal to 1 molecule.


3) Therefore, there are 4 carbon atoms, 4 hydrogen atoms and 2 sulfur atoms in each molecule of C₄H₄S₂.


4) Then, you just have to multiply the corresponding subscript of the element times the number of molecules (25 in this case) to find the number of atoms of that kind.


5) These are the calculations for each element in the molecule C₄H₄S₂.


i) C: 4 × 25 = 100

ii) H: 4 × 25 = 100

iii) S: 2 × 25 = 50.


6) The question is about H only, so the answer is that there are 100 hydrogen atoms in 25 molecules of C₄H₄S₂.

5 0
2 years ago
Read 2 more answers
the mass of sample X is 20.0g. it was placed in a graduated cylinder and the water level rose from A to B. what is the density o
MatroZZZ [7]

Answer: 4.0 g/mL

Explanation:

The volume increased by 5.0 mL. Recall that the number of significant figures is equal to the number of certain values you can read plus one. Here, the volume increased from 14.0 mL to 19.0 mL, so the volume of X is 5.0 mL.

3 0
2 years ago
A sample contains 2.2 g of the radioisotope niobium-91 and 15.4 g of its daughter isotope, zirconium-91. how many half-lives hav
dybincka [34]

Answer: 3

Explanation: This is a radioactive decay and all the radioactive process follows first order kinetics.

Equation for the reaction of decay of _{19}^{40}\textrm{K} radioisotope follows:

Moles of zirconium=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{15.4}{91}=0.17moles  

Moles of niobium=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{2.2}{91}=0.024moles  

_{41}^{91}\textrm{Nb}\rightarrow _{40}^{91}\textrm{Zr}+_{+1}^0e

By the stoichiometry of above reaction,

1 mole of _{40}^{91}\textrm{Zr} is produced by 1 mole _{41}^{91}\textrm{Nb}

So, 0.17 moles of _{40}^{91}\textrm{Zr} will be produced by = \frac{1}{1}\times 0.17=0.17\text{ moles of }_{40}^{91}\textrm{Nb}

Amount of _{82}^{212}\textrm{K}

decomposed will be = 0.17 moles

Initial amount of _{40}^{91}\textrm{Nb}  will be = Amount decomposed + Amount left = (0.17 + 0.024)moles =0.194 moles

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives = 0.024

a_o = Initial amount of the reactant = 0.194

n = number of half lives= ?

Putting values in above equation, we get:

0.024=\frac{0.194}{2^n}

n=3

Therefore, 3 half lives have passed.

3 0
2 years ago
Read 2 more answers
Which has not been suggested as a reasonably practical way to store large amounts of hydrogen in relatively small spaces for its
Yakvenalex [24]

Answer: A. Liquefy hydrogen under pressure and store it much as we do with liquefied natural gas today.

Explanation:

Current Hydrogen storage methods fall into one of two technologies;

  1. <em>physical storage</em> where compressed hydrogen gas is stored under pressure or as a liquid; and
  2. <em>chemical storage</em>, where the hydrogen is bonded with another material to form a hydride and released through a chemical reaction.

Physical storage solutions are commonly used technologies but are problematic when looking at using hydrogen to fuel vehicles. Compressed hydrogen gas needs to be stored under high pressure and  requires large and heavy tanks. Also, liquid hydrogen boils at -253°C (-423°F) so it needs to be stored cryogenically with heavy insulation and actually contains less hydrogen compared with the same volume of gasoline.  

Chemical storage methods allow hydrogen to be stored at much lower pressures and offer high storage performance due to the strong binding of hydrogen and the high storage densities. They also occupy relatively smaller spaces than either compressed hydrogen gas or liquified hydrogen. A large number of chemical storage systems are under investigation, which involve hydrolysis reactions, hydrogenation/dehydrogenation reactions, ammonia borane and other boron hydrides, ammonia, and alane etc.

Other practical storage methods being researched that focuses on storing hydrogen as a lightweight, compact energy carrier for mobile applications include;

  • Metal hydrides  e.g. LiH
  • Nanostructured metal hydrides
  • Non-metal hydrides
  • Carbohydrates
  • Synthesized hydrocarbons
  • Aluminum
  • Liquid organic hydrogen carriers (LOHC)
  • Encapsulation , e.t.c.
5 0
2 years ago
The metallic radius of a potassium atom is 231 pm. What is the volume of a potassium atom in cubic meters?
Sauron [17]
1 pm = 10∧-10 cm
Therefore, 230 pm is equivalent to 2.3 ×10∧-8 cm.
Atom is in the shape of a sphere,
The volume of a sphere is given by 4/3πr³
Thus, volume of the atom = 4/3π( 2.3 ×10∧-8)³
                                          = 4/3 (3.142 ×12.167×10∧-24
                                           = 5.096 ×10∧-23 cm³
but 1m³= 1000000cm³
Therefore, the volume of the atom = 5.096 ×10∧-29 m³
8 0
2 years ago
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