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scoundrel [369]
2 years ago
12

You construct a circuit containing some component C, along with other circuit elements. You want to simultaneously measure the c

urrent through C and the voltage across C while it remains connected to the rest of the circuit. Indicate where you would connect an ammeter (A) and a voltmeter (V) to perform these measurements. Fill any remaining gaps with wires as needed to complete the connection with the rest of the circuit.

Physics
1 answer:
astra-53 [7]2 years ago
6 0

Answer:

The position of the ammeter is in series down the component. While the voltmeter must be connected in parallel. Its position is the gap through the component C.

The positions of one or the other are indicated in the image.

Explanation:

An ammeter is defined as a device used to measure current. Its unit is the ampere. While a voltmeter is used in the measurement of the potential difference between two points. Its unit is the volt. The ammeter must be connected in series with the point at which the current is to be measured, while the voltmeter must be connected in parallel.

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A plane initially traveling at 200 m/s due west experiences a 10 m/s head wind coming from the opposite direction. A). What will
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Ok so it would be late and the relative velocity would be 190 m/s because 200 m/s - 10 m/s is 190 m/s. Hope this helps.
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Which statement about images is correct? a) A virtual image cannot be formed on a screen. b) A virtual image cannot be viewed by
ankoles [38]

Answer:

A). A virtual image cannot be formed on a screen.

Explanation:

A virtual image can not be formed on a screen.

For image:

1.A virtual image can be viewed by the unaided eye.

2. A real image must be erect or maybe inverted.

3.Mirrors can produce virtual as well as real image ,it depends on which type of mirror is.

4.A virtual image can be photographed.

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2 years ago
A turntable rotates counterclockwise at 76 rpm . A speck of dust on the turntable is at 0.47 rad at t=0. What is the angle of th
icang [17]

To solve this exercise it is necessary to apply the kinematic equations of angular motion.

By definition we know that the displacement when there is constant angular velocity is

\theta= \theta_0 +\omega t

From our given data we know that,

\omega = 76\frac{rev}{min}

\omega = 76\frac{rev}{min}(\frac{2\pi rad}{1rev})(\frac{1 min}{60s})

\omega = 7.958rad/s

Moreover we know that

\theta_0 = 0.47 rad

Therefore for time t=8.1s we have,

\theta= \theta_0+ \omega t

\theta= 0.47+(7.958)(8.1)

\theta = 64.9298rad

That number in revolution is:

\theta = 64.9298rad(\frac{1rev}{2\pi})

\theta = 15.108 Revolutions

Here, we see that there are 15 complete revolutions

And 0.108 revolutions i not complete, so the tunable rotation is

\theta_{net} = 0.108*2\pi=0.216\pi

Therefore the angle of the speck at a time 8.1s is 0.216\pi

4 0
2 years ago
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slavikrds [6]
Answer:
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explanation:
8 0
2 years ago
Read 2 more answers
a rod of some material 0.20 m long elongates 0.20 mm on heating from 21 to 120°c. determine the value of the linear coefficient
Rufina [12.5K]

Answer:

The value of the linear coefficient of thermal expansion is : α=1.01 *10⁻⁵ (ºC)⁻¹

Explanation:

Li = 0.2m

ΔL = 0.2 mm = 0.0002m

T1 = 21ºC

T2 = 120ºC

ΔT =99ºC

α =ΔL/(Li*ΔT)

α =0.0002m /(0.2m * 99ºC)

α = 1.01 *10⁻⁵   (ºC)⁻¹

4 0
2 years ago
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