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2 years ago

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2. Imagine you have just baked a pizza in the oven. You've only let it cool for a minute, but you're

1 answer:

GaryK [48]2 years ago

3 0

Answer:

You should take a bite near the crust that contains very little sauce.

Explanation:

Specific heat capacity is amount of heat a one gram of substance must absorb or lose to change its temperature by one degree Celsius.

The sauce has water in it. Water has a high high heat capacity,( i.e 4.186 J/g °C, ) which means that the sauce takes more time to cool, as a result the sauce is still be hot even after few minutes of cooling, as compared to crust which has less sauce so it will cool faster.

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1.50 × 104 J of energy is transferred thermally into a huge tank filled with liquid water. The water temperature remains constan

posledela

Answer:

53j/k

Explanation:

ΔH = TΔS => ΔS = ΔH/T = 1.5 x 10⁴ joules/283 Kelvin = 53 joules/K

3 0

2 years ago

What mass of oxygen reacts when 84.9 g of iron is consumed in the following reaction: Fe+O2= Fe2O3

konstantin123 [22]

First we will calculate the number of moles of Iron:
$n = \frac{m}{M}
$ , where n is the number of moles, m is the mass of iron in the reaction and M is the Atomic weight.
$n= \frac{84.9}{55.845} = 1,52$ moles of Iron.
The same number of moles of Oxygen will take part in the reaction.
So $1,52= \frac{mOxygen}{32}$ where 32 is the Atomical Weight of Oxygen (16 x 2).
=> $mOxygen=32*1,52=48,64$ g

6 0

2 years ago

Read 2 more answers

Determine the normality of the following solutions note the species of interest is H 95 g of PO4 3- in 100mL solution

Aliun [14]

Answer : The normality of the solution is, 30.006 N

Explanation :

Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.

Mathematical expression of normality is:

$\text{Normality}=\frac{\text{Gram equivalent of solute}}{\text{Volume of solution in liter}}$

or,

$\text{Normality}=\frac{\text{Weight of solute}}{\text{Equivalent weight of solute}\times \text{Volume of solution in liter}}$

First we have to calculate the equivalent weight of solute.

Molar mass of solute $PO_4^{3-}$ = 94.97 g/mole

$\text{Equivalent weight of solute}=\frac{\text{Molar mass of solute}}{\text{charge of the ion}}=\frac{94.97}{3}=31.66g.eq$

Now we have to calculate the normality of solution.

$\text{Normality}=\frac{95g}{31.66g.eq\times 0.1L}=30.006eq/L$

Therefore, the normality of the solution is, 30.006 N

5 0

2 years ago

The combustion of propane is represented by the following chemical equation. C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(l) The standard enthalp

wariber [46]

Answer:

ΔH°c = -2219.9 kJ

Explanation:

Let's consider the combustion of propane.

C₃H₈(g) + 5 O₂(g) ⟶ 3 CO₂(g) + 4 H₂O(l)

We can find the standard enthalpy of the combustion (ΔH°c) using the following expression.

ΔH°c = [3 mol × ΔH°f(CO₂(g)) + 4 mol × ΔH°f(H₂O(l))] - [1 mol × ΔH°f(C₃H₈(g)) + 5 mol × ΔH°f(O₂(g))]

ΔH°c = [3 mol × (-393.5 kJ/mol) + 4 mol × (-285.8 kJ/mol)] - [1 mol × (-103.8 kJ/mol) + 5 mol × (0 kJ/mol)]

ΔH°c = -2219.9 kJ

7 0

2 years ago

Select all that reasons that the reaction contents does not conduct at this low point.

Alexxx [7]

It's all three of the answers

5 0

2 years ago