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Romashka-Z-Leto [24]
2 years ago
8

In a test tube you add 2 mL of saturated chlorine water followed by about 1 mL of an organic solvent such as heptane (or cyclohe

xane). The test tube is shaken and you notice that the heptane layer has a yellow color. To this mixture you then add 1 mL of 0.1 M N a I. After shaking you notice a color change from yellow to purple in the heptane layer. What can you conclude about Cl2 and I minus from this experiment
Chemistry
1 answer:
bazaltina [42]2 years ago
7 0

Answer:

The organic compounds (heptane/cyclohexane) will get dissolve in Cl₂ water forming a yellow colored solution.

When NaI is added into it, the following reaction between NaI and Cl2 takes place;

Cl₂ + NaI ⇒ I₂ + NaCl

In above reaction, oxidation state of Cl is getting reduced from 0 in Cl2 to -1 in NaCl.

Therefore, Cl2 is getting reduced and acting as an oxidizing agent in the reaction. While I⁻ is getting oxidised annd acting as a reducing agent

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By mistake, a quart of oil was dumped into a swimming pool that measures 25.0 m by 30.0 m. The density of the oil was 0.750 g/cm
kondor19780726 [428]

The oil slick thick = 1.256 x 10⁻⁴ cm

<h3>Further explanation</h3>

Volume is a derivative quantity derived from the length of the principal

The unit of volume can be expressed in liters or milliliters or cubic meters

The conversion is

1 cc = 1 cm3

1 dm = 1 Liter

1 L = 1.06 quart

<em>so for 1 quart = 0.943 L</em>

\tt 0.943~L=0.943\times 10^{-3}m^3

Volume of oil dumped = volume of swimming pool

\tt 0.943\times 10^{-3}~m^3=25\times 30\times h(h=thick)\\\\h=\dfrac{0.943\times 10^{-3}}{750~m^2}=1.257\times 10^{-6}~m=\boxed{\bold{1.256\times 10^{-4}~cm}}

3 0
2 years ago
When CO2(g) reacts with H2(g) to form C2H2(g) and H2O(g), 23.3 kJ of energy are absorbed for each mole of CO2(g) that reacts. Wr
kupik [55]

Answer:

2CO_{2}(g)+5H_{2}(g)\rightarrow C_{2}H_{2}(g)+4H_{2}O(g)-46.6kJ

Explanation:

As energy is absorbed therefore it is an endothermic reaction. Hence energy value should be written in the product side with a negative sign.

Reaction:  CO_{2}(g)+H_{2}(g)\rightarrow C_{2}H_{2}(g)+H_{2}O(g)

C balance: 2CO_{2}(g)+H_{2}(g)\rightarrow C_{2}H_{2}(g)+H_{2}O(g)

H and O balance: 2CO_{2}(g)+5H_{2}(g)\rightarrow C_{2}H_{2}(g)+4H_{2}O(g)

Here 2 moles of CO_{2} react. So, energy absorbed during the reaction is (2\times 23.3) kJ or 46.6 kJ

Energy balance: 2CO_{2}(g)+5H_{2}(g)\rightarrow C_{2}H_{2}(g)+4H_{2}O(g)-46.6kJ

Balanced thermochemical equation:

2CO_{2}(g)+5H_{2}(g)\rightarrow C_{2}H_{2}(g)+4H_{2}O(g)-46.6kJ

3 0
2 years ago
Which answer choices correctly describe properties of covalent compounds?<br> Select all that apply.
Lana71 [14]

Answer:

Explanation:

A covalent compound is made when two or more nonmetal atoms bond by sharing valence electrons. The shared valence electrons between two nonmetal atoms is called a covalent bond. Covalent bonds are formed when two atoms begin sharing electrons

7 0
2 years ago
Read 2 more answers
Exactly 56 grams of iron is mixed with 156 grams of oxygen. The elements are heated and they react. What best describes which re
Mars2501 [29]

Answer:

Explanation:

The chemical expression for the reaction between iron and oxygen is:

4Fe(s)  +  3O₂ (g)  \to 2Fe₂O₃ (s)

The number of moles of Fe = mass of Fe/ molecular mass of Fe

The number of moles of Fe = 56 g/ 55.845 g/mol

The number of moles of Fe = 1.002 moles of Fe

The number of moles of oxygen = mass of oxygen/ molecular mass of oxygen

The number of moles of oxygen = 156 g /32 g/mol

The number of moles of oxygen = 4.875 moles of oxygen

Assume that Fe is the limiting reactant, the number of Fe₂O₃ can be calculated as:

moles of Fe₂O₃ = 1.002 mole of Fe × 2 moles of Fe₂O₃/ 4 moles of Fe

moles of Fe₂O₃ = 0.501 mole of Fe₂O₃

Assume that O₂ is the limiting factor, the number of Fe₂O₃ is:

moles of Fe₂O₃ = 4.875 moles of O₂ × 2 moles of Fe₂O₃/ 3 moles of O₂

moles of Fe₂O₃ = 3.25 mole of Fe₂O₃

Thus, after the reaction is complete, Fe and O₂ contain different moles of Fe₂O₃. Only Fe gets consumed in the reaction and it is the limiting factor.

8 0
1 year ago
What mass of 2-bromopropane could be prepared from 25.5 g of propene? Assume a 100% yield of product.
Mamont248 [21]

Answer:

78.46 grams of  2-bromopropane could be prepared from 25.5 g of propene

Explanation:

C_3H_6+HBr\rightarrow C_3H_7Br

Moles of propene = \frac{25.5 g}{39 g/mol}=0.6538 mol

According to reaction, 1 mole of propene gives 1 mole of propane.

Then 0.6538 moles of bromo-propane will give:

0.6538 mol\times 120 g/mol=78.46 g

78.46 grams of  2-bromopropane could be prepared from 25.5 g of propene.

5 0
2 years ago
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