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jenyasd209 [6]
1 year ago
10

A galvanic (voltaic) cell consists of an electrode composed of zinc in a 1.0 M zinc ion solution and another electrode composed

of copper in a 1.0 M copper(II) ion solution, connected by a salt bridge. Calculate the standard potential for this cell at 25 °C. Standard reduction potentials can be found here.
Chemistry
1 answer:
s2008m [1.1K]1 year ago
6 0

<u>Answer:</u> The standard potential for the given cell is 0.89 V

<u>Explanation:</u>

The standard reduction potentials for zinc and copper are:

E^o_{(Cu^{2+}/Cu)}=+0.13V\\E^o_{(Zn^{2+}/Zn)}=-0.76V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, copper will undergo reduction reaction will get reduced.

Zinc will undergo oxidation reaction and will get oxidized.

Oxidation half reaction:  Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction:  Cu^{2+}+2e^-\rightarrow Cu

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.13-(-0.76)=0.89V

Hence, the standard potential for the given cell is 0.89 V

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Give the major organic product of the reaction of o-methylaniline with benzenediazonium chloride [(phn≡n)+ cl-].
Wewaii [24]
Benzene diazonium salt reacts by coupling with activated aromatic rings as aniline and phenol and in this case diazonium acts as weak electrophile and react with substitution on para position according to the following reaction:

7 0
2 years ago
The enthalpy of combustion of benzoic acid (C6H5COOH) is commonly used as the standard for calibrating constant-volume bomb calo
Anit [1.1K]
<h3>Answer:</h3>

28.96 kJ/°C

<h3>Explanation:</h3>

We are given;

  • Enthalpy change (ΔH) = −3226.7 kJ/mol
  • The reaction is exothermic since the heat change is negative;
  • Mass of benzoic acid = 3.1007 g
  • Temperature change (21.84°C to 24.67°C) = 2.83°C

We are required to find the heat capacity of benzoic acid;

<h3>Step 1: Moles of benzoic acid </h3>

Moles = Mass ÷ molar mass

Molar mass of benzoic = 122.12 g/mol

Therefore;

Moles = 3.1007 g ÷ 122.12 g/mol

          = 0.0254 moles

<h3>Step 2: Determine the specific heat capacity </h3>

Heat change for 1 mole = 3226.7 kJ

Moles of Benzoic acid = 0.0254 moles

But;

Specific heat capacity × ΔT = Moles × Heat change

  cΔT = nΔH

Therefore;

Specific heat capacity,c = nΔH ÷ ΔT

                                     = (3226.7 kJ × 0.0254 moles) ÷ 2.83°C

                                    = 28.96 kJ/°C

Therefore, the specific heat capacity of benzoic acid is 28.96 kJ/°C

7 0
2 years ago
A gas mixture at 0°C and 1.0atm contains 0.010mol of H2, 0.015mol of O2, and 0.025mol of N2. Assuming ideal behavior, what is th
Olegator [25]

Answer:

PH₂ = 0.2 atm

C) About 0.20atm, because H2 comprises 20% of the total number of moles of gas.

Explanation:

To determine the partial pressure of hydrogen gas (H2) in the mixture,

Partial pressure H₂ = Ptotal * xH₂

xH₂ = Mole fraction of H₂ = ∩H₂ / ( ∩H₂ + ∩O₂ + ∩N₂)

xH₂ = 0.01 / (0.01 + 0.015 + 0.025)

xH₂ = 0.01/0.05

xH₂ = 0.2

therefore

PH₂ = pT * xH₂

PH₂ = 1.0 atm * 0.2

PH₂ = 0.2 atm

so the correct option is C)  About 0.20atm, because H2 comprises 20% of the total number of moles of gas.

7 0
2 years ago
If 0.640 g of beautiful blue crystals of azulene is dissolve in 99 g of benzen, the resulting solutions boils at 80.23 degrees c
devlian [24]

This problem handles<em> boiling-point elevation</em>, which means we will use the formula:

ΔT = Kb * m

Where ΔT is the difference of Temperature between boiling points of the solution and the pure solvent (Tsolution - Tsolvent). Kb is the ebullioscopic constant of the solvent (2.64 for benzene), and m is the molality of the solution.

Knowing that benzene's boiling point is 80.1°C, we <u>solve for m</u>:

Tsolution - Tsolvent = Kb * m

80.23 - 80.1 = 2.64 * m

m = 0.049 m

We use the definition of molality to <u>calculate the moles of azulene</u>:

0.049 m = Xmoles azulene / 0.099 kgBenzene

Xmoles azulene = 4.87 x10⁻³ moles azulene

We use the mass and the moles of azulene to<u> calculate its molecular weight</u>:

0.640 g / 4.875 x10⁻³ mol = 130.28 g/mol

<em>A molecular formula that would fulfill that molecular weight</em> is C₁₀H₁₀. So that's the result of solving this problem.

The actual molecular formula of azulene is C₁₀H₈.

6 0
2 years ago
Suppose you wanted to make a buffer of exactly ph 7.00 using kh2po4 and na2hpo4. if the final solution was 0.10 m in kh2po4, wha
OleMash [197]

Answer:- 0.138 M

Solution:- The buffer pH is calculated using Handerson equation:

pH=pKa+log(\frac{base}{acid})

KH_2PO_4 acts as a weak acid and Na_2HPO_4 as a base which is pretty conjugate base of the weak acid we have.

The acid hase two protons(hydrogen) where as the base has only one proton. So, we could write the equation as:

H_2PO_4^-\rightleftharpoons H^++HPO_4^-^2

Phosphoric acid gives protons in three steps. So, the above equation is the second step as the acid has only two protons and the base has one proton.

So, we will use the second pKa value. The acid concentration is given as 0.10 M and we are asked to calculate the concentration of the base to make a buffer of exactly pH 7.00.

Let's plug in the values in the equation:

7.00=6.86+log(\frac{base}{0.10})

7.00-6.86=log(\frac{base}{0.10})

0.14=log(\frac{base}{0.10})

Taking antilog:

10^0^.^1^4=\frac{base}{0.10}

1.38=\frac{base}{0.10}

On cross multiply:

[base] = 1.38(0.10)

[base] = 0.138

So, the concentration of the base that is Na_2HPO_4 required to make the buffer is 0.138M.

5 0
1 year ago
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