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weeeeeb [17]
2 years ago
6

A straight wire lies along the y-axis initially carrying a current of 10 A in the positive y-direction. The current decreases an

d reverses to 10 A in the negative y-direction, the change in current happening at a uniform rate. In the 1st quadrant a square conducting coil has 2 sides parallel to the y-axis and the other 2 sides parallel to the x-axis. The side of the coil nearest and parallel to the straight wire is at a distance equal to the length of one of the sides of the square. As the current is going from 10 A in one direction to 10 A in the other, in which direction is the induced current in this side of the square coil nearest to the straight wire

Physics
1 answer:
Elan Coil [88]2 years ago
8 0

Answer:

Explanation:

The magnetic field due to straight wire is into the square coil.

As the current in straight wire decreases the magnetic flux in the coil decreases . The induced magnetic field is into the coil.The induced current is along +y direction

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The researcher requires the force on the wire to point upward with a magnitude of 4.2x10-4 N. The length of the wire that is in
lorasvet [3.4K]

Answer:

The magnetic force can be found by using the following equation:

F_B = IL\times B

Let’s first deal with the magnitude, then we will figure out the direction by using the right hand rule.

4.2\times 10^{-4} = (30\times 10^{-3})\times  (50\times10^{-3}) \times B\\4.2 \times 10^{-4} = 1500 \times 10^{-6}\times B\\(28\times 10^{-4})\times 10^2 = B\\B = 28\times 10^{-2}

The direction of the L is equal to the direction of the current. So, the direction of the L is to the right. The required force is to be pointed upward.

By the right hand rule the magnetic field should be directed towards ‘into the plane’.

Explanation:

In the questions regarding the magnetic field, the cross product and the directions of the vectors are crucial. So, you should use right-hand rule efficiently.

Right-hand rule: A \times B = C

Point your four fingers (except the thumb) towards the same direction as A.

Point your palm towards the same direction as B.

Your thumb should show the direction of C.

5 0
2 years ago
A submarine completed a 450 km training with an average speed of 50 km/h. For the first 180 km, it travelled at an average speed
Kryger [21]

Answer:

45km/hr

Explanation:

Total distance=450km

Total speed=50km/hr

Total time= distance/speed

=450/50

=9hrs

distance a=180km

speed a=60km/hr

Time a=180/60

=3hrs

Distance b=450-180=270km

Speed b=?

Time b=270/speed b

Total time=time a + time b

9=3+(270/speed b)

270/speed b =9-3

270/speed b =6

6*speed b =270

Speed b=270/6

Speed b=45km/hr

4 0
2 years ago
A hot (70°C) lump of metal has a mass of 250 g and a specific heat of 0.25 cal/g⋅°C. John drops the metal into a 500-g calorimet
Gnom [1K]

Answer:

d. 37 °C

Explanation:

m_{m} = mass of lump of metal = 250 g

c_{m} = specific heat of lump of metal  = 0.25 cal/g°C

T_{mi} = Initial temperature of lump of metal = 70 °C

m_{w} = mass of water = 75 g

c_{w} = specific heat of water = 1 cal/g°C

T_{wi} = Initial temperature of water = 20 °C

m_{c} = mass of calorimeter  = 500 g

c_{c} = specific heat of calorimeter = 0.10 cal/g°C

T_{ci} = Initial temperature of calorimeter = 20 °C

T_{f} = Final equilibrium temperature

Using conservation of heat

Heat lost by lump of metal = heat gained by water + heat gained by calorimeter

m_{m} c_{m} (T_{mi} - T_{f}) = m_{w} c_{w} (T_{f} - T_{wi}) +  m_{c} c_{c} (T_{f} - T_{ci}) \\(250) (0.25) (70 - T_{f} ) = (75) (1) (T_{f} - 20) + (500) (0.10) (T_{f} - 20)\\T_{f} = 37 C

6 0
2 years ago
Two billiard balls of equal mass are traveling straight toward each other with the same speed. They meet head-on in an elastic c
Rus_ich [418]

Answer:

0 kg m/s before and after collision

Explanation:

Let m, v be the mass and speed of the 2 balls, respectively, before the collision. Since they have the same mass and same speed but in opposite direction, the total momentum of the system would be:

P = mv - mv = 0 kg m/s

As the collision is elastic. The total momentum after the collision is the same as the total momentum before the collision, which is 0.

5 0
2 years ago
How are chargeable cells different from ordinary dry cells​
topjm [15]
Ordinary cells can convert chemical energy to electrical energy only, but rechargeable cells can also store electrical energy into chemical energy and vice versa. You will study more about it in your higher classes. secondary cells can be recharged and used again but dry cells cannot be recharged.
6 0
2 years ago
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