answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mazyrski [523]
2 years ago
3

Consider a cube. On 5 sides of the cube, there is an electric field that comes out perpendicular to that side, of value E. (a) I

f there is no charge inside the cube, what is the field (direction and magnitude) perpendicular to the remaining side? (b) If there is a charge Q inside the cube, how does your answer to (a) change?
Physics
1 answer:
4vir4ik [10]2 years ago
7 0

Answer:

Explanation:

There are six sides or faces  in a cube. We shall apply Gauss's law here to solve the problem.

a ) If there is no charge inside the cube , total net flux coming out of all the faces will be nil. Suppose area of each face is one squire metre.

If Ex be the required flux coming out of sixth face .

Total flux coming out of six faces of cube = Ex + 5 E

Since total flux coming out is nil

Ex + 5 E = 0

Ex =  - 5E

At the sixth face , electric field will be - 5E . The negative sign indicates that field will be in opposite direction ie it will be towards the inside of the cube.

b ) According to Gauss's theorem , total flux coming out this time will be

Q / ε₀

So this time total flux coming out will be equal to Q / ε₀.

Ex + 5 E  = Q / ε₀.

Ex = Q / ε₀ - 5 E.

If Q / ε₀ > 5 E

Ex will be positive , so its direction will be outward .

If Q / ε₀ < 5 E

Ex will be negative  , so its direction will be inward.

You might be interested in
A charge Q is placed on the x axis at x = +4.0 m. A second charge q is located at the origin. If Q = +75 nC and q = −8.0 nC, wha
Stells [14]

Answer:

23.1 N/C

Explanation:

OP = 3 m , OQ = 4 m

PQ = \sqrt{4^{2}+3^{2}}=5 m

q = - 8 nC, Q = 75 nC

Electric field at P due to the charge Q is

E_{1}=\frac{KQ}{PQ^{2}}=\frac{9\times 10^{9}\times 75\times 10^{-9}}{25}=27 N/C

Electric field at P due to the charge q is

E_{2}=\frac{Kq}{PO^{2}}=\frac{9\times 10^{9}\times 8\times 10^{-9}}{9}=8 N/C

According to the diagram, tanθ = 3/4

Resolve the components of E1 along x axis and along y axis.

So, Electric field along X axis, Ex = - E1 Cos θ

Ex = - 27 x 4 / 5 = - 21.6 N/C

Electric field along y axis, Ey = E1 Sinθ - E2

Ey = 27 x 3 /5 - 8 = 8.2 N/C

The resultant electric field at P is given by

E=\sqrt{E_{x}^{2}+E_{y}^{2}}=\sqrt{(-21.6)^{2}+(8.2)^{2}}=23.1 N/C

3 0
2 years ago
Two 8.0 Ω lightbulbs are connected in a 12 V series circuit. What is the power of both glowing bulbs?
V125BC [204]

Answer:

18 W

Explanation:

Applying,

P = V²/R.................. Equation 1

Where P = Power of both glowing bulbs, V = Voltage, R = Combined Resistance of both bulbs

Since: It is a series circuit,

Then,

R = R1+R2............. Equation 2

Where R1= Resistance of the first bulb, R2 = Resistance of the second bulb

Given: R1 = R2 = 8 Ω

Substitute into equation 1

R = 8+8

R = 16 Ω

Also Given: V = 12 V

Substitute into equation 1

P = 12²/8

P = 144/8

P = 18 W

7 0
2 years ago
Variations in the resistivity of blood can give valuable clues about changes in various properties of the blood. Suppose a medic
Elena-2011 [213]

Answer:

Answer:

1.1 x 10^9 ohm metre

Explanation:

diameter = 1.5 mm

length, l = 5 cm

Potential difference, V = 9 V

current, i = 230 micro Ampere = 230 x 10^-6 A

radius, r = diameter / 2 = 1.5 / 2 = 0.75 x 10^-3 m

Let the resistivity is ρ.

Area of crossection

A = πr² = 3.14 x 0.75 x 0.75 x 10^-6 = 1.766 x 10^-6 m^2

Use Ohm's law to find the value of resistance

V =  i x R

9 = 230 x 10^-6 x R

R = 39130.4 ohm

Use the formula for the resistance

R=\rho \frac{l}{A}

\rho =\frac{RA}{l}

\rho =\frac{39130.4\times 0.05}{1.766\times 10^{-6}}

ρ = 1.1 x 10^9 ohm metre

Explanation:

7 0
2 years ago
A car wheel turns through 277° in 10.7 s. Calculate the angular speed of the wheel.
slava [35]

Answer:

The angular speed of the wheel is 0.452 rad/s

Explanation:

The angle through which the car wheel turns, Δθ = 277° = 277/360 × 2·π radian

The time it takes for the car wheel to turn, Δt = 10.7 s

The angular speed, ω is given by the following equation;

Angular \ speed = \dfrac{Change \ in \ angular \ rotation }{Change \ in \ time} = \dfrac{\Delta \theta}{\Delta t}

Substituting the known values for Δθ and Δt gives;

Angular \ speed = \dfrac{\dfrac{277 ^{\circ}}{360 ^{\circ }  }  \times 2 \times \pi \ radian}{10.7 \ seconds} \approx 0.452 \ rad/s

The angular speed of the wheel = 0.452 rad/s

3 0
2 years ago
For the first 10 seconds a squirrel runs 3 m/s to look for an acorn. The next 5 seconds he eats an acorn that he finds. Afterwar
Gala2k [10]

Distance covered by the squirrel to look for an acorn :

d = ( 3 m/s ) × 10 s = 30 m.

Time taken to eat an Acron is 5 seconds.

Time taken to cover distance of 30 m with 2 m/s speed is :

T=\dfrac{30}{2}\ s= 15 \ s

Therefore, total time take to  get back to where he started is ( 10+5+15 ) = 30 s.

Hence, this is the required solution.

7 0
2 years ago
Other questions:
  • An object of mass 5 kilograms is moving across a surface in a straight line with a speed of 3.5 meters/second. What amount of fo
    11·1 answer
  • A quarterback throws a football at 40km/hr to a receiver 50yd away. How much time does it take the ball to reach the receiver
    14·1 answer
  • Joel uses a claw hammer to remove a nail from a wall. He applies a force of 40 newtons on the hammer. The hammer applies a force
    14·2 answers
  • An electron is moving in the vicinity of a long, straight wire that lies along the z-axis. The wire has a constant current of 8.
    10·1 answer
  • An uncharged 30.0-µF capacitor is connected in series with a 25.0-Ω resistor, a DC battery, and an open switch. The battery has
    7·2 answers
  • The capacitors in each circuit are fully charged before the switch is closed. Rank, from longest to shortest, the length of time
    12·1 answer
  • A positively-charged particle is released near the positive plate of a parallel plate capacitor. a. Describe its path after it i
    11·1 answer
  • Rod A has twice the diameter of rod B, but both are made of iron and have the same initial length. Both rods are now subjected t
    11·1 answer
  • if a net horizontal force of 175 N is applied to a bike whos mass is 43 kg what acceleration is produced
    15·1 answer
  • A cliff diver running 3.60 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 2.00 s later
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!