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34kurt
1 year ago
5

The gap between electrodes in a spark plug is 0.060 cm. Producing an electric spark in a gasoline-air mixture requires an electr

ic field of 3.0 × 106 V/m. What minimum potential difference must be supplied by the ignition circuit to start a car?
Physics
1 answer:
VladimirAG [237]1 year ago
6 0

The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V

<u>Explanation:</u>

Given data,

E= 3 ×10 ⁶ Δx=0.06/100

We have to find the minimum potential difference

E= -ΔV/Δx

ΔV=- E × Δx

ΔV =-3 ×10 ⁶ . 0.06/100

ΔV=-1800 V

The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V

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The charge Q on the sheet is

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\sigma=\frac{Q}{A}\\ =\frac{4*10^-^9C}{0.0289 m^2} \\ =1.389*10^-^7C/m^2

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1 year ago
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Hope i helped
Have a good day :)

 
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