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2 years ago

How to TPWK according to you

Physics

2 answers:

REY [17]2 years ago

7 0

Answer:

You can treat people with kindness by accepting people for who they are, and not judging them for being themselves. Always respect people!!!

Explanation: I really love Harry Styles lol

Karo-lina-s [1.5K]2 years ago

6 0

Answer:

TPWK is an acronym which stands for treat people with kindness. It encourages people to respect and love others in all situations.

Explanation:

Treat people with kindness (TPWK) is one of the major attitudes that must be imbibed by everyone. This would give room for more love and genuine kindness for others which would make the world a better place to live. Because people will live with the consciousness that others come first.

There are variuos ways and manner to treat people with kindness which can be simplified as having genuine love for others. When people are kind to one another, then life would be worth living.

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A skydiver deploys his parachute when he is 1000m directly above his desired landing spot. He then falls through the air at a st

insens350 [35]

We can calculate his resultant speed.

Resultant speed is:
v^2 = 5^2 + 1,9^2
v = 5,349 m/s

Now we need to find angle between resultant speed and vertical speed.
cos(alpha) = 5/5.349 = 0.9347
alpha = 20,8 degrees

Answer is 20,8 degrees

8 0

2 years ago

A bee wants to fly to a flower located due North of the hive on a windy day. The wind blows from East to West at speed 6.68 m/s.

Aleonysh [2.5K]

Answer: $53.31\°$ East of North

Explanation:

We have the following data:

Speed of the wind from East to West: $6.68 m/s$

Speed of the bee relative to the air: $8.33 m/s$

If we graph these speeds (which in fact are velocities because are vectors) in a vector diagram, we will have a right triangle in which the airspeed of the bee (its speed relative to te air) is the hypotense and the two sides of the triangle will be the Speed of the wind from East to West (in the horintal part) and the speed due North relative to the ground (in the vertical part).

Now, we need to find the direction the bee should fly directly to the flower (due North):

$sin \theta=\frac{Windspeed-from-East-to-West}{Speed-bee-relative-to-air}$

$sin \theta=\frac{6.68 m/s}{8.33 m/s}$

Clearing $\theta$ :

$\theta=sin^{-1} (\frac{6.68 m/s}{8.33 m/s})$

$\theta=53.31\°$

6 0

2 years ago

Stu wanted to calculate the resistance of a light bulb connected to a 4.0 V battery, with a resulting current of 0.5 A. He used

Dimas [21]

His answer was incorrect because according to ohm's law the formula used should have been R=V/I instead of multiplying and the answer should be 8ohms

4 0

2 years ago

Read 2 more answers

A girl is shown at position A on a swing when the seat is directly below the support bar. The seat is then at height A as shown

MrRa [10]

Answer:

1. The potential energy of the swing is the greatest at the position B.

2. As the swing moves from point B to point A, the kinetic energy is increasing.

Explanation:

Even though the syntax of the text is not completely clear, likely because it accompanies a drawing that is not included, it results clear that the posittion A is where the seat is at the lowest position, and the position B is upper.

The gravitational potential energy is directly proportional to the height of the objects with respect to some reference altitude. Thus, when the seat is at the position A the swing has the smallest potential energy and when the seat is at the position B the swing has the greatest potential energy.

Regarding the forms of energy, as the swing moves from point B to point A, it is going downward, gaining kinetic energy (speed) at the expense of the potential energy (losing altitude). When the seat passes by the position A, the kinetic energy is maximum and the potential energy is miminum. Then the seat starts to gain altitude again, losing the kinetic energy and gaining potential energy, up to it gets to the other end,

7 0

2 years ago

Read 2 more answers

A rock of mass m is thrown horizontally off a building from a height h. the speed of the rock as it leaves the thrower's hand at

Stells [14]

The correct answer is 3) $K_f = \frac{1}{2}mv_0^2 + mgh$ .

In fact, the total energy of the rock when it leaves the thrower's hand is the sum of the gravitational potential energy U and of the initial kinetic energy K:
 $E=U_i+K_i=mgh + \frac{1}{2}mv_0^2$
As the rock falls down, its height h from the ground decreases, eventually reaching zero just before hitting the ground. This means that U, the potential energy just before hitting the ground, is zero, and the total final energy is just kinetic energy:
 $E=K_f$ 
But for the law of conservation of energy, the total final energy must be equal to the tinitial energy, so E is always the same. Therefore, the final kinetic energy must be
 $K_f = mgh + \frac{1}{2}mv_0^2$

7 0

2 years ago