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LenaWriter [7]
1 year ago
14

What is the law of conservation of energy as it applies to exothermic dissolution processes?Energy given off by the system durin

g dissolution equals the energy absorbed by the surroundings.Energy given off by the system during dissolution is less than the energy absorbed by the surroundings.Energy given off by the system during dissolution is greater than the energy absorbed by the surroundings.Energy given off by the system during dissolution may be greater or less than the energy absorbed by the surroundings.
Chemistry
1 answer:
Pani-rosa [81]1 year ago
4 0

Answer:

The energy given off by the system during dissolution is less than the energy absorbed by the surroundings.

Explanation:

Energy is used to break bonds in reactants, and energy is released when new bonds form in products. Endothermic reactions absorb energy, and exothermic reactions release energy. The law of conservation of energy states that matter cannot be created or destroyed.

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Suppose now that you wanted to determine the density of a small crystal to confirm that it is silicon. From the literature, you
SSSSS [86.1K]

Answer:

CHCL3= 11.73 mL

CHBr3= 8.268 mL

Explanation:

Let x be the mL of CHCl3 and y be the mL of CHBr3, then we have:

y+x = 20 mL

1.492x+2.89y=2.07* 20.0 mL

3 0
1 year ago
Which element can form a chloride with a general formula of MCl2 or MCl3
zhannawk [14.2K]
Oxidation state number can be used to determine the unknown element in these two compounds. They are used to determine how many electrons are given, taken or shared to form compounds.

Recall the elementary rules of oxidation numbers.

1. The sum of all oxidation numbers in a neutral compound is zero.
2. Chlorine, bromine, iodine have oxidation number of -1 ( except compounds with fluorine and oxygen)

Let oxidation number of element M be x.
Check rule 2. Chlorine has -1 oxidation number.

Now we write an equation of MCl₂ (neutral compound)
x + (2 * -1)= 0 ⇒ x₁= +2

For MCl₃
x + (3 * -1)=  0 ⇒ x₂= +3

So element has 2 different oxidation number in compounds, +2 and +3.

The element is iron (Fe) since it has +2 and +3  oxidation numbers in the compounds.

You need to learn it by hard. Unfortunately there is not an easier way to work out with these oxidation numbers.

The answer is iron (Fe).

5 0
1 year ago
In a covalently bonded molecule, the number of electrons that an atom shares with others is usually equal to the number of elect
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In the last shell (valence shell)
8 0
2 years ago
List the number of each type of atom on the left side of the equation 2C10H22(l)+31O2(g)→20CO2(g)+22H2O(g)
ValentinkaMS [17]

Answer: There are 20 carbons atoms, 62 oxygen atoms and 44 carbon atoms on the left side of the equation.

Explanation:

In the given chemical reaction:

2C_{10}H_{22}(l)+31O_2(g)\rightarrow 20CO_2(g)+22H_2O(g)

Reactants side = Left side

Number of atoms =

Coefficient × Number of atoms of an element in a unit molecular formula

Number of carbon atoms = 2 × 10 = 20

Number of oxygen atoms = 31 × 2 = 62

Number of hydrogen atoms =  2 × 22 = 44

8 0
2 years ago
Los automóviles actuales tienen “parachoques de 5 mi/h (8 km/h)” diseñados para comprimirse y rebotar elásticamente sin ningún d
PilotLPTM [1.2K]

Answer:

k = 23045 N/m

Explanation:

To find the spring constant, you take into account the maximum elastic potential energy that the spring can support. The kinetic energy of the car must be, at least, equal to elastic potential energy of the spring when it is compressed to its limit. Then, you have:

K=U\\\\\frac{1}{2}Mv^2=\frac{1}{2}kx^2    (1)

M: mass of the car = 1050 kg

k: spring constant = ?

v: velocity of the car = 8 km/h

x: maximum compression of the spring = 1.5 cm = 0.015m

You solve the equation (1) for k. But first you convert the velocity v to m/s:

v=8\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=2.222\frac{m}{s}

k=\frac{Mv^2}{x^2}=\frac{(1050kg)(2.222m/s)^2}{(0.015m)^2}=23045\frac{N}{m}

The spring constant is 23045 N/m

3 0
1 year ago
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