Answer:
CHCL3= 11.73 mL
CHBr3= 8.268 mL
Explanation:
Let x be the mL of CHCl3 and y be the mL of CHBr3, then we have:
y+x = 20 mL
1.492x+2.89y=2.07* 20.0 mL
Oxidation state number can be used to determine the unknown element in these two compounds. They are used to determine how many electrons are given, taken or shared to form compounds.
Recall the elementary rules of oxidation numbers.
1. The sum of all oxidation numbers in a neutral compound is zero.
2. Chlorine, bromine, iodine have oxidation number of -1 ( except compounds with fluorine and oxygen)
Let oxidation number of element M be x.
Check rule 2. Chlorine has -1 oxidation number.
Now we write an equation of MCl₂ (neutral compound)
x + (2 * -1)= 0 ⇒ x₁= +2
For MCl₃
x + (3 * -1)= 0 ⇒ x₂= +3
So element has 2 different oxidation number in compounds, +2 and +3.
The element is iron (Fe) since it has +2 and +3 oxidation numbers in the compounds.
You need to learn it by hard. Unfortunately there is not an easier way to work out with these oxidation numbers.
The answer is iron (Fe).
Answer: There are 20 carbons atoms, 62 oxygen atoms and 44 carbon atoms on the left side of the equation.
Explanation:
In the given chemical reaction:

Reactants side = Left side
Number of atoms =
Coefficient × Number of atoms of an element in a unit molecular formula
Number of carbon atoms = 2 × 10 = 20
Number of oxygen atoms = 31 × 2 = 62
Number of hydrogen atoms = 2 × 22 = 44
Answer:
k = 23045 N/m
Explanation:
To find the spring constant, you take into account the maximum elastic potential energy that the spring can support. The kinetic energy of the car must be, at least, equal to elastic potential energy of the spring when it is compressed to its limit. Then, you have:
(1)
M: mass of the car = 1050 kg
k: spring constant = ?
v: velocity of the car = 8 km/h
x: maximum compression of the spring = 1.5 cm = 0.015m
You solve the equation (1) for k. But first you convert the velocity v to m/s:


The spring constant is 23045 N/m