Determine ΔT if T1 = 45oC and T2 = 13oC
1 answer:
You might be interested in
<u>Answer:</u> This illustrates law of conservation of mass.
<u>Explanation:</u>
Dalton's theory is based on mainly two laws which are law of conservation of mass and law of constant proportion.
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
The chemical equation for the decomposition of calcium carbonate follows:
We are given:
Mass of calcium carbonate = 100 grams
Mass of calcium oxide = 56 grams
Mass of carbon dioxide = 44 grams
Total mass on reactant side = 100 g
Total mass on product side = 56 + 44 = 100 g
As, the total mass on reactant side is equal to the total mass on product side.
Thus, this illustrates law of conservation of mass.
Answer:
The mass percentage of calcium carbonated reacted is 2.5%.
Explanation:
The reaction is:
Thus the Kp of the equilibrium will be:
Kp = partial pressure of carbon dioxide [as the other are solid]
Moles of calcium carbonate initially present =
Let us apply ICE table to the equilibrium given:
Initial 0.2 0 0
Change -x +x +x
Equilibrium 0.2-x x x
Kp = partial pressure of carbon dioxide
Kp = Kc(RT)ⁿ
where n = difference in the number of moles of gaseous products and reactants
for given reaction n = 1
R = gas constant = 8.314 J /mol K
T = temperature = 800 ⁰C = 1073 K
Putting values
Kc =
Kc =
On calculating
x = 0.005
where x = the moles of calcium carbonate dissociated or reacted.
Percentage of the moles or mass reacted = %