Coefficient of static friction = tan(a) = 0.4
r = 740 m
g = 9.8 m/s²
v = √(9.8 × 740 × 0.4) m/s
v ≈ 53.85908 m/s
r = 740 m
g = 9.8 m/s²
v = √(9.8 × 740 × 0.4) m/s
v ≈ 53.85908 m/s
If Faraday had used a more powerful battery in his experiments with electromagnetic induction, what effect would this have had o
1 answer:
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Answer:
The young tree, originally bent, has been brought into the vertical position by adjusting the three guy-wire tensions to AB = 7 lb, AC = 8 lb, and AD = 10 lb. Determine the force and moment reactions at the trunk base point O. Neglect the weight of the tree.
C and D are 3.1' from the y axis B and C are 5.4' away from the x axis and A has a height of 5.2'
Explanation:
See attached picture.
The strength of the magnetic field is
Explanation:
According to Faraday's Law, the magnitude of the induced emf in the coil is equal to the rate of changeof the flux linkage through the coil:
(1)
where
N = 505 is the number of turns in the coil
is the change in magnetic flux through the coil
is the time interval
The coil is rotated from a position perpendicular to the Earth's magnetic field to a position parallel to it, so the final flux is zero, and the magnitude of the flux change is simply equal to the initial flux:
where
B is the strength of the magnetic field
A is the area of the coil
is the angle between the normal to the coil and the field
The area of the coil can be written as
where
is its radius
Substituting everything into eq.(1) and solving for B, we find:
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Answer:
3.5 cm
Explanation:
mass, m = 50 kg
diameter = 1 mm
radius, r = half of diameter = 0.5 mm = 0.5 x 10^-3 m
L = 11.2 m
Y = 2 x 10^11 Pa
Area of crossection of wire = π r² = 3.14 x 0.5 x 10^-3 x 0.5 x 10^-3
= 7.85 x 10^-7 m^2
Let the wire is stretch by ΔL.
The formula for Young's modulus is given by
ΔL = 0.035 m = 3.5 cm
Thus, the length of the wire stretch by 3.5 cm.
Answer:
So the acceleration of the child will be
Explanation:
We have given angular speed of the child
Radius r = 4.65 m
Angular acceleration
We know that linear velocity is given by
We know that radial acceleration is given by
Tangential acceleration is given by
So total acceleration will be