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Lemur [1.5K]
2 years ago
10

On occasion, it has been found that the oxidation of borneol doesn't go to completion (possibly because of poor stirring or insu

fficient Oxone). This reaction would probably be easy to monitor via TLC, however. Which component should have a lower Rf, and why
Chemistry
1 answer:
seraphim [82]2 years ago
3 0

Answer:

Check the explanation

Explanation:

Here, Nitrogen (N) undergoes oxidation and Chlorine (Cl) undergoes reduction.

To answer your question:

N is oxidized from an oxidation number of -3 to an oxidation number of -1.

Cl is reduced from oxidation number of +1 to an oxidation number of -1.

Now,

Borneol should have a lower Rf because of boiling point.

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How might a collision between Neptune and Halley's Comet<br> affect Neptune's orbit?
Damm [24]

Answer:

It will mess up the orbit around the sun

Explanation:

7 0
2 years ago
A sample of pure lithium chloride contains 16% lithium by mass. What is the % lithium by mass in a sample of pure lithium carbon
Anna35 [415]

Answer:

Percentage lithium by mass in Lithium carbonate sample = 19.0%

Explanation:

Atomic mass of lithium = 7.0 g; atomic mass of Chlorine = 35.5 g; atomic mass of carbon = 12.0 g; atomic mass of oxygen = 16.0 g

Molar mass of lithium chloride, LiCl = 7 + 35.5 = 42.5 g

Percentage by mass of lithium in LiCl = (7/42.5) * 100% = 16.4 % aproximately 16%

Molar mass of lithium carbonate, Li₂CO₃ = 7 * 2 + 12 + 16 * 3 =74.0 g

Percentage by mass of lithium in Li₂CO₃ = (14/74) * 100% = 18.9 % approximately 19%

Mass of Lithium carbonate sample = 2 * 42.5 = 85.0 g

mass of lithium in 85.0 g Li₂CO₃ = 19% * 85.0 g = 16.15 g

Percentage by mass of lithium in 85.0 g Li₂CO₃ = (16.15/85.0) * 100 % = 19.0%

Percentage lithium by mass in Lithium carbonate sample = 19.0%

3 0
2 years ago
It took many of the metals several minutes to begin to react. Once the reaction was initiated, several of these metals continued
notsponge [240]

Answer:

Passivation of Oxide layers of the metals.

Explanation:

Passivation is a non-electrolytic finishing process that makes most metals rust-resistant. The prosses removes free iron from the surface by using either nitric or citric acid. When this happens, it results to an inert, protective oxide layer that is very slow or less likely to chemically react with air and cause corrosion.

Passivity caused many of the metals several minutes to begin to react. Once the finishing process that makes metals less likely to react was eroded, reaction was initiated vigorously.

8 0
2 years ago
When 60.0 g of CH4 reacts with excess O2, the actual yield of CO2 is 112 g. What is the percent yield? CH4(g) + 2O2(g) → CO2(g)
zepelin [54]

Answer:

67.88% is the percent yield.

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CH_4(g) + 2O_2(g)\rightarrow CO_2(g) + 2H_2O(g)

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According to reaction,1 mole of methane gives 1 mole of carbon dioxide gas, then 3.75 moles of methane will give :

\frac{1}{1}\times 3.75 mol =3.75 mol of carbon dioxide gas

Mass of 3.75 moles of carbon dioxide gas:

3.75 mol × 44 g/mol = 165 g

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The percentage yield of the reaction :

Yield\%=\frac{\text{actual yield}}{\text{Theoretical yield}}\times 100

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Learn more :brainly.com/question/24535523

3 0
2 years ago
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