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Oduvanchick [21]
2 years ago
4

Use the observation in the first column to answer the question in the second column. observation question The enthalpy of vapori

zation of Substance C is bigger than that of Substance D. Which has the higher boiling point? Substance C Substance D Neither, C and D have the same boiling point. It's impossible to know without more information. At 1atm pressure, Substance E boils at 89.°C and Substance F boils at 128.°C. Which has a higher enthalpy of vaporization? Substance E Substance F Neither, E and F have the same enthalpy of vaporization. It's impossible to know without more information. At −3°C, Substance A has a vapor pressure of 147.torr and Substance B has a vapor pressure of 177.torr. Which has a higher boiling point? Substance A Substance B Neither, A and B have the same boiling point. It's impossible to know without more information.
Chemistry
1 answer:
frosja888 [35]2 years ago
8 0

Answer:

See explaination

Explanation:

1. Substance C

With Vapor pressure (VP) of C = 136 torr and VP of D = 186 torr. Since VP (C) < VP (D), this entaills that one needs to supply more energy to get C into the vapor phase. Hence, enthalpy of vaporization of C will be higher.

2. Substance A

B.pt (A) = 109 C

B,pt (B) = 125 C

Having A boils at a lower temperature than B, this automatically will make A to have a higher vapor pressure.

3. Substance E

Since E has a lower enthalpy of vaporization, it can be brought into the vapor phase with lower energy as compared to F. Hence, E will have a higher vapor pressure.

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4.8g of calcium is added to 3.6g of water. The following reaction occurs
notka56 [123]
Q1)
the number of moles can be calculated as follows
number of moles = mass present / molar mass
number of moles is the amount of substance.
4.8 g of Ca was added therefore mass present of Ca is 4.8 g
molar mass of Ca is 40 g/mol 
molar mass is the mass of 1 mol of Ca
therefore if we substitute these values in the equation 
number of moles of Ca = 4.8 g / 40 g/mol = 0.12 mol
0.12 mol of Ca is present 

q2)
next we are asked to calculate the number of moles of water present 
again we can use the same equation to find the number of moles of water
number of moles = mass present / molar mass
3.6 g of water is present 

sum of the products of the molar masses of the individual elements by the number of atoms 
H - 1 g/mol and O - 16 g/mol 
molar mass of water = (1 g/mol x 2 ) + 16 g/mol = 18 g/mol 
molar mass of H₂O is 18 g/mol 
therefore number of moles of water  = 3.6 g / 18 g/mol = 0.2 mol 
0.2 mol of water is present 
8 0
2 years ago
Which runner has greater kinetic energy: a 46-kilogram runner moving at a speed of 8 meters per second or a 92-kilogram runner m
Lena [83]
Runner a has a greater kinetic energy
8 0
2 years ago
How would you combine reactions A–C, shown below, to obtain the overall reaction: $$ Please select all that apply.
snow_lady [41]

Answer:

By eating a sandwich

Explanation:

your welcome nigel

4 0
2 years ago
If the speed of a vehicle increases by 22%, by what factor does its kinetic energy increase?
Mila [183]

Answer:

The kinetic increases by 48.84 %

Explanation:

The expression for the kinetic energy is:-

K.E.=\frac{1}{2}\times mv^2

Where, m is the mass of the object

v is the velocity of the object

Let the new velocity is:- v'

v is increased by 22 %. Thus, v' = 1.22 v

So, the new kinetic energy is:-

K.E.'=\frac{1}{2}\times mv'^2=\frac{1}{2}\times m{1.22}^2=\frac{1}{2}\times mv^21.4884=1.4884K.E.

<u>Thus, the kinetic increases by 48.84 %</u>

7 0
2 years ago
Read 2 more answers
Which statement correctly compares what occurs when molecules absorb photons in the microwave region with what occurs when molec
ValentinkaMS [17]

Answer:

d.) Microwave photons cause the molecules to increase their rotational energy states, whereas infrared photons cause electrons in the molecules to increase their electronic energy states.

Explanation:

Microwave: transitions in the molecular rotational levels

Infrared: transitions in molecular vibrational levels

UV/Visible: transitions in electronic energy levels.

5 0
1 year ago
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