Match the sequence number with the energy transformations from the water behind a hydroelectric dam to the lighting of a light b
1 answer:
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Answer:
35,79 meters
Explanation:
So, we got an archer, and we got a target. Lets call the distance between this two d.
Now, the archer fires the arrow, that, in a time travels the distance d with a speed
of 40 m/s and hits the target. We can see that the equation will be:
Immediately after this, the arrow produces a muffled sound, which will travel the distance d at 340 m/s in a time . Obtaining :
.
Finally, the sound reaches the archer, exactly 1 second after he fired the bow, so:
.
This equation allows us to write:
.
Plugging this relationship in the distance equation for the sound:
.
Now, we can replace d from the first equation, and obtain:
.
Now, we can just work a little bit:
.
Now, we can just plug this value into the first equation:
Answer:
f_D = =3.24 N/m
Explanation:
data given
properties of air
k = 0.0288 W/m.K
WE KNOW THAT
Reynold's number is given as
= 1.941 *10^4
drag coffecient is given as
solving for f_D
Drag coffecient for smooth circular cylinder is 1.1
therefore Drag force is
f_D = =3.24 N/m