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Solnce55 [7]
2 years ago
6

A geologist took this aerial photo of a location where a river flows out of a mountain range.

Chemistry
2 answers:
Monica [59]2 years ago
8 0

Answer:

yup its A-alluvial fan

Explanation:

rodikova [14]2 years ago
3 0

Answer:

A<u> alluvial fan</u>

Explanation:

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What is the ratio of the diffusion rates of cl2 and o2? rate cl2 : o2 = 0.47 0.67 0.45 0.69 1.5?
matrenka [14]
The  ratio  of  the diffusion  rate  of Cl2  and   O2   is 1.5

    calculation
rate  of diffusion Cl2/ rate   of  diffusion  O2 =√  molar mass of Cl2/ molar mass  of O2

molar  mass of Cl2  = 35.5 x2 = 71  g/mol
molar  mass O2  = 16 x2 =32g/mol

that  is    rate  of diffusion Cl2/ rate  of  diffusion of O2  =√ 71/ 32=  1.5
7 0
2 years ago
In the compound k[co(c2o4)2(h2o)2] (where c2o42– = oxalate) the oxidation number and coordination number of cobalt are, respecti
ehidna [41]
Let's Assign Symbols to molecules like,

                    C₂O₄  =  X
and 
                    H₂O   =  Y
Then,
                                K [ Co (X)₂ (Y)₂ ]

As, Potassium (K) has a O.N  =  +1

To neutralize, the coordination sphere must have -1 oxidation number.
So,
                                    [ Co (X)₂ (Y)₂ ]  =  -1
As,
           O.N of X  = -2
Then 
       O.N of (X)₂  =  -4

Also,
O.N of H₂O is zero as it is neutral, So,

                                    [Co - 4 + 0 ]  =  -1
Or,
                                    Co  =  -1 + 4

                                    Co  =  +3

Result:
          Oxidation Number of Coordination Sphere is -1 and Oxidation Number of Cu is +3.
6 0
2 years ago
Read 2 more answers
In the electrochemical cell using the redox reaction below, the anode half reaction is ________. Sn4+ (aq) + Fe (s) → Sn2+ (aq)
kenny6666 [7]

Answer:

The anode half reaction is : Fe(s)\rightarrow Fe^{2+}(aq.)+2e^{-}

Explanation:

In electrochemical cell, oxidation occurs in anode and reduction occurs in cathode.

In oxidation, electrons are being released by a species. In reduction, electrons are being consumed by a species.

We can split the given cell reaction into two half-cell reaction such as-

Oxidation (anode): Fe(s)\rightarrow Fe^{2+}(aq.)+2e^{-}

Reduction (cathode): Sn^{4+}(aq.)+2e^{-}\rightarrow Sn^{2+}(aq.)

------------------------------------------------------------------------------------------------------------

overall: Fe(s)+Sn^{4+}(aq.)\rightarrow Fe^{2+}(aq.)+Sn^{2+}(aq.)

So the anode half reaction is : Fe(s)\rightarrow Fe^{2+}(aq.)+2e^{-}

8 0
2 years ago
A large cylindrical tank contains 0.750 m3 of nitrogen gas at 27°C and 7.50 * 103 Pa (absolute pressure). The tank has a tight‐f
Nuetrik [128]

Answer: The answer is 68142.4 Pa

Explanation:

Given that the initial properties of the cylindrical tank are :

Volume V1= 0.750m3

Temperature T1= 27C

Pressure P1 =7.5*10^3 Pa= 7500Pa

Final properties of the tank after decrease in volume and increase in temperature :

Volume V2 =0.480m3

Temperature T2 = 157C

Pressure P2 =?

Applying the gas law equation (Charles and Boyle's laws combined)

P1V1/T1 = P2V2/T2

(7500 * 0.750)/27 =( P2 * 0.480)/157

P2 =(7500 * 0.750* 157) / (0.480 *27)

P2 = 883125/12.96

P2 = 68142.4Pa

Therefore the pressure of the cylindrical tank after decrease in volume and increase in temperature is 68142.4Pa

8 0
2 years ago
A chemical reaction is done in the setup shown , resulting in a change of mass. What will happen if the same reaction is done in
irina1246 [14]
<h2>Answer:</h2>

The mass of the system will remain the same if there is no conversion of mass to energy in the reaction.

<h3>Explanation:</h3>
  • If the system is closed, then according to the law of mass conservation the mass of the reaction system will remain the same.
  • <u><em>Law of conservation of the mass: In simple words, it is described as the mass of a closed system can never be changed, it may transfer from one form to another or change into energy.</em></u>
  • But if the reaction involves energy transfer like heat or light production, in this case, the mass can be changed.
5 0
2 years ago
Read 2 more answers
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