All categories

2 years ago

Give reason: Photo chemical decomposition reaction finds application in photography.

Chemistry

1 answer:

RideAnS [48]2 years ago

5 0

Answer:

Photo chemical is caused by the chemical reaction of light. It's initiated by the absorption of energy in the form of light.

Explanation:

When the picture is developed, the thiosulfate dissolved the silver bromide that had been exposed to light more easily than the one that had been kept in the dark,

You might be interested in

A toy car is placed at 0 on a number line. It moves 9 cm to the left, then 4 cm to the right, and then 6 cm to the left. What is

snow_lady [41]

Answer:

Explanation:

The total distance traveled by the toy cay would be 19 cm.

The total distance traveled should not be mistaken for total displacement. While displacement measures the distance and direction from the starting position of the toy car relative to its final position, the total distance traveled is calculated by adding all the movements of the toy car together. Hence;

Total distance traveled = 9 + 4 + 6 = 19 cm

7 0

2 years ago

Read 2 more answers

choose the reaction that illustrates delta H *f for Ca(NO3)2.(A) Ca (s) + N2 (g) + 3O2 ---> Ca(NO3)2 (s)(B) Ca2 (aq) + 2 NO3-

kompoz [17]

Answer: The correct answer is Option A.

Explanation:

Standard enthalpy of formation is the change in enthalpy of one mole of a substance present at the standard state that is 1 atm of pressure and 298 K of temperature. The substance is formed from its pure elements under the same conditions.

We are given a chemical compound having chemical formula $Ca(NO_3)_2$

This compound is formed by the combination of calcium, nitrogen and oxygen elements.

The chemical equation for the formation of $Ca(NO_3)_2$ from the components in their standard states follows:

$Ca+N_2+3O_2\rightarrow Ca(NO_3)_3$

Hence, the correct answer is Option A.

3 0

2 years ago

PLEAS HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! DUE TONIGHT

Jobisdone [24]

Answer:

It is required answer.

Explanation:

Given that :

1. using balanced chemical equation:

ammonium acetate:

The balanced equation is:

NH₃ + H₂O ===> NH₄OH

when ammonia gas dissolves in water then we get the base in form of ammonium hydroxide.

When NH₄OH reacts with CH₃COOH then we get ammonium acetate and water

NH₄OH + CH₃COOH ===> [CH₃COO]- & NH₄+ & H₂O

So, we can say that,

when we are adding an acid and a base together then we get the product of H₂O and given elements.

2. addition of barium hydroxide to sulfuric acid:

the balanced equation is

H₂SO4+ Ba(OH)₂--> BaSO₄+ 2H₂O

when acid and base reacts together than we get barium sulphate and water

when sulfuric acid and barium hydroxide.

Hence, it is required answer.

8 0

2 years ago

What volume is occupied by 0.34 moles of Helium gas?

guapka [62]

Answer:

0.65882352941

Explanation:

5 0

2 years ago

Read 2 more answers

How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m

Pie

Answer: The mass of sodium acetate that must be added is 30.23 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol$

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})$

$pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of acetic acid = 4.74

$[CH_3COONa]=?mol$

$[CH_3COOH]=0.200mol$

pH = 5.00

Putting values in above equation, we get:

$5=4.74+\log(\frac{[CH_3COONa]}{0.200})$

$[CH_3COONa]=0.364mol$

To calculate the mass of sodium acetate for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

$0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g$

Hence, the mass of sodium acetate that must be added is 30.23 grams

7 0

2 years ago