Answer:
v = 2.21 m/s
Explanation:
The foreman had released the box from rest at a height of 0.25 m above the ground.
We need to find the speed of the crate when it reaches the bottom of the ramp. Let v is the velocity at the bottom of the ramp. It can be calculated using conservation of energy as follows :
So, its velocity at the bottom of the ramp is 2.21 m/s.
Answer:
Magnetic field at the center of the loop
Explanation:
It is given that total length of wire is 2 m and number of circular loop is 5 turns.
Therefore ,
We know , magnetic field at the center of loop is given by :
Putting all values in above equation we get :
Hence , this is the required solution.
Answer:
Explanation:
Given:
Initial velocity of the vehicle,
distance between the car and the tree,
time taken to respond to the situation,
acceleration of the car after braking,
Using equation of motion:
..............(1)
where:
final velocity of the car when it hits the tree
initial velocity of the car when the tree falls
acceleration after the brakes are applied
distance between the tree and the car after the brakes are applied.
Now for this situation the eq. (1) becomes:
(negative sign is for the deceleration after the brake is applied to the car.)