- Calcular la magnitud de la fuerza eléctrica entre dos cargas cuyos valores son: q1 = 3.5 coulomb, q2 = 6 coulomb, al estar sep
1 answer:
Answer:
FE = 1.17*10^12 N
Explanation:
The magnitude of the electric force is given by the following formula:
( 1 )
q1 = 3.5C
q2 = 6C
r = 0.4m
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
You replace the values of q1, q2, r and k in the expression (1):
hence, the magnitude of the electric force is 1.17*10^12 N
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Answer:
<em>You would use the kinematic formula:</em>
Explanation:
The upwards vertical motion is ruled by the equation:
Where:
Naming Δy = y - y₀, the equation becomes:
Then, you just need to substitute with Δy = 0.1m, t = 2s, and g = 9.8m/s², ans solve for the intital vertical velocity.
Answer:
a) t=10.2s
b) The 2g-cube moves first
Explanation:
Since the electric force is the same on both cubes and so is the coefficient of static friction, the first one to move will be the one with less mass.
So, on the 2g-cube the sum of forces are:
Replacing the friction on the first equation:
Thus
The electric force is:
Solving for q:
q=71.44nC
This amount divided by the rate at which they are being charged:
t = 71.44nC / 7nC/s = 10.2s
Answer:
Explanation:
The free body diagram of the block on the slide is shown in the below figure
Since the block is in equilibrium we apply equations of statics to compute the necessary unknown forces
N is the reaction force between the block and the slide
For equilibrium along x-axis we have
Using value of N from equation β in α we get value of force as
Applying values we get
