The efficiency of the first Carnot engine is
n1 = 1 - Th/T
The efficiency of the second Carnot engine is
n2 = 1 - T/Tc
The total efficiency of the engines put in series is
n = 1 - Th/Tc
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Answer:
(a) Angle of incidence for violet is more than the angle of incidence for red
(b) 2.4°
Explanation:
refractive index for violet , v = 1.66
refractive index for red, nR = 1.61
wavelength for violet, λv = 400 nm
wavelength for red, λR = 700 nm
Angle of refraction, r = 30°
(a) Let iv be the angle of incidence for violet.
Use Snell,s law
nv = Sin iv / Sin r
1.66 = Sin iv / Sin 30
Sin iv = 0.83
iv = 56°
Use Snell's law for red
nR = Sin iR / Sin r
where, iR be the angle of incidence for red
1.61 = Sin iR / Sin 30
Sin iR = 0.805
iR = 53.6°
So, the angle of incidence for violet is more than red.
(b) iv - iR = 56° - 53.6° = 2.4°
Answer and Explanation: Kinetic energy is related to movement: it is the energy an object possesses during the movement. it is calculated as:
For the object thrown in the air:
![K=\frac{1}{2}.2.[v(t)]^{2}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7D.2.%5Bv%28t%29%5D%5E%7B2%7D)
Kinetic energy of the object as a function of time:
Potential energy is the energy an object possesses due to its position in relation to other objects. It is calculated as:
For the object thrown in the air:
Potential energy as function of time:
Total kinetic and potential energy, also known as mechanical energy is
TME = 
+ (
)
TME = 1752
The expression shows that total energy of an object thrown in the air is constant and independent of time.
Answer: 
Explanation:
Where;
a = acceleration
V2 = final velocity
V1 = initial velocity
t = time
If John runs 1.0 m/s first, we assume this is V1. He accelerates to 1.6 m/s; this is V2.
Answer:
<em>a) Fvt cosθ</em>
<em>b) Fv cosθ</em>
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Explanation:
Each horse exerts a force = F
the rope is inclined at an angle = θ
speed of each horse = v
a) In time t, the distance traveled d = speed x time
i.e d = v x t = vt
also, the resultant force = F cosθ
Work done W = force x distance
W = F cosθ x vt = <em>Fvt cosθ</em>
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b) Power provided by the horse P = force x speed
P = F cosθ x v
P = <em>Fv cosθ</em>
