<u>Answer:</u> The mass of ammonia produced is 28.22 g
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For hydrogen gas:</u>
Given mass of hydrogen gas = 10.0 g
Molar mass of hydrogen gas = 2 g/mol
Putting values in equation 1, we get:
- <u>For nitrogen gas:</u>
Given mass of nitrogen gas = 80.0 g
Molar mass of nitrogen gas = 28 g/mol
Putting values in equation 1, we get:
The given chemical equation follows:
By Stoichiometry of the reaction:
3 moles of hydrogen gas reacts with 1 mole of nitrogen gas
So, 5 moles of hydrogen gas will react with = of nitrogen gas
As, given amount of nitrogen gas is more than the required amount. So, it is considered as an excess reagent.
Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
3 moles of hydrogen gas produces 1 mole of ammonia
So, 5 moles of hydrogen gas will produce = of ammonia
Now, calculating the mass of ammonia from equation 1, we get:
Molar mass of ammonia = 17 g/mol
Moles of ammonia = 1.66 moles
Putting values in equation 1, we get:
Hence, the mass of ammonia produced is 28.22 g