All categories

2 years ago

What might happen if an octopus we're chased by a predator

Chemistry

2 answers:

Elanso [62]2 years ago

7 0

Answer:

They will try to defend themselves

Explanation:

STatiana [176]2 years ago

5 0

Answer:

octopuses will shoot a dark liquid, sometimes called ink, at the thing that scared them. ... If an octopus does get caught — no problem. They can lose arms and regrow them.

Explanation:

You might be interested in

Lin received 200 new laptops to be issued to company employees. Lin was asked to set them up and distribute them to everyone on

OleMash [197]

Answer:

Inventory management documentation

Explanation:

Inventory management documentation is a system of tracking the company's stock. In ordinary terms, Inventory management refers to the sequential processes which include; ordering, storing, and using a company's inventory. The scope of inventory management also covers the management of raw materials, components, and finished products as well as warehousing and processing such items.

Inventory management documentation will surely aid Lin to know what employee has received his/her laptop and who has not from his inventory records. The scope of Inventory management documentation transverses the entire spectrum of a supply chain.

5 0

2 years ago

Read 2 more answers

Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and allowed to reach equilibrium described by the equation N2O4(g) 2N

Amanda [17]

Answer : The correct option is, (a) 0.44

Explanation :

First we have to calculate the concentration of $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

Now we have to calculate the dissociated concentration of $N_2O_4$ .

The balanced equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(aq)$

Initial conc. 1.0 M 0

At eqm. conc. (1.0-x) M (2x) M

As we are given,

The percent of dissociation of $N_2O_4$ = $\alpha$ = 28.0 %

So, the dissociate concentration of $N_2O_4$ = $C\alpha=1.0M\times \frac{28.0}{100}=0.28M$

The value of x = $C\alpha$ = 0.28 M

Now we have to calculate the concentration of $N_2O_4\text{ and }NO_2$ at equilibrium.

Concentration of $N_2O_4$ = 1.0 - x = 1.0 - 0.28 = 0.72 M

Concentration of $NO_2$ = 2x = 2 × 0.28 = 0.56 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.56)^2}{0.72}=0.44$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.44

8 0

2 years ago

How many hydrogen bonds can CH2O make to water

VladimirAG [237]

Hydrogen bonds are not like covalent bonds. They are nowhere near as strong and you can't think of them in terms of a definite number like a valence. Polar molecules interact with each other and hydrogen bonds are an example of this where the interaction is especially strong. In your example you could represent it like this:

H2C=O---------H-OH 

But you should remember that the H2O molecule will be exchanging constantly with others in the solvation shell of the formaldehyde molecule and these in turn will be exchanging with other H2O molecules in the bulk solution. 

Formaldehyde in aqueous solution is in equilibrium with its hydrate. 

H2C=O + H2O <-----------------> H2C(OH)2

5 0

2 years ago

Which monatomic ions would you expect radium (z = 88) and selenium (z = 34) to form?

makvit [3.9K]

1) Radium will form Ra²⁺ ions, because it is metal with two valence electrons (7s²) and it will lost two electrons to have electric configuration like noble gas radon (Z=86).

Electroic configuration of radium atom:

₈₈Ra 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶4d¹⁰4f¹⁴5s²5p⁶5d¹⁰6s²6p⁶7s².

2) Selenium wil form Se²⁻ ions, because it is nonmetal and it has six valence electrons (4s²4p⁴), it will gain two electrons to have electron configuration like noble gas krypton (Z=36).

Electronic configuration of selenium atom: ₃₄Se 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁴.

6 0

2 years ago

Read 2 more answers

As noted in Assignment 1.4.1., alkylation of benzene with 1-chlorobutane in the presence of AlCl3 gives both butylbenzene and (1

Sunny_sXe [5.5K]

Answer:

Use the Bromotriflouride catalyst, BF₃

Explanation:

The BF₃ is most likely to yield less desired side products. The effect lies in the reaction mechanism.

BF₃ is a Lewis acid. Its role is to promote the ionization of the HF. This is achieved through the electrophilic mechanism. The reaction mechanism is as follows:

2 - methylpropene + H-F-BF₃ → H-F + H₃C + benzene

butylbenzene + F-BF₃ → tert-butylbenzene + H-F + BF₃ (regenerated catalyst)

6 0

2 years ago