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weqwewe [10]
2 years ago
6

If a plant needs to make 12.6 g of glucose(c6h1206), how many grams of water are required?

Chemistry
1 answer:
hichkok12 [17]2 years ago
8 0

Answer: 7.6 g of water are required to make 12.6 g of glucose

Explanation:

Moles is calculated by using the formula:

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

{\text {moles of glucose}}=\frac{12.6g}{180g/mol}=0.07moles

The balanced chemical equation is:

6CO_2+6H_2O\rightarrow C_6H_{12}O_6+6O_2

According to stoichiometry:

1 mole of glucose is produced by = 6 moles of water

Thus 0.07 moles of glucose is produced by =\frac{6}{1}\times 0.07=0.42 moles of water

Mass of water required =moles\times {\text {Molar mass}}=0.42mol\times 18g/mol=7.6g

Thus 7.6 g of water are required to make 12.6 g of glucose

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Sedbober [7]

The two strands must be separated like the two sides of a zipper, by breaking the weak hydrogen bonds that link the paired bases.

<u>Explanation:</u>

  • A double helix structure formed by two polypeptide chains is separated like the two sides of a zipper. A zipper is formed by breaking the weak hydrogen bonds that link the paired bases. During replication, an enzyme "Helicase" travels down the DNA and splits the chain and it forms 2 separate strands.
  • The two DNA strand which has the same sequence must be separated like the two sides of a zipper by breaking weak hydrogen bases. During base pair-rule, the strand are unzipped and each strands is copied.

     

3 0
2 years ago
When a known quantity of compound, at a known concentration, is added to a known volume of another compound to determine the con
Vladimir [108]

Answer:

A titration

Explanation:

A common example of a titration is when we have an acid of unknown concentration, so we add a known volume of a base of known concentration. This process lets us determine the concentration of the acid.

By definition, a titration is a quantitative analysis, as we determine how much of an analyte is there in a sample. However, <u>there are quantitative analyzes which are not titrations</u>. This is why the most appropiate answer is<em> a titration</em>.

5 0
2 years ago
If A is slowly added to a solution containing 0.0500 M of B and 0.0500 M of C, which solid will precipitate first? The solubilit
OleMash [197]

Answer:

AC₄ will precipitate out first.

Explanation:

A solid will precipitate out if the ionic product of the solution exceeds the solubility product.

Let us check the ionic product

a) A₂B₃

Ionic product = [A]²[B]³

[A] = say "s"

[B] = 0.05 , [B]³ = (0.05)³ = 0.000125

2.3 X 10⁻⁸ = [A]²(0.000125)

[A] = 0.0136

b) AC₄

Ionic product = [A] [C]⁴

[A] = "s"

[A][0.05]⁴ = 4.10 X 10⁻⁸

[A]=0.00656 M

So for ionic product to exceed solubility product, we need less concentration of A in case of AC₄.

5 0
2 years ago
The bond dissociation energy to break 4 bond(s) in 1 mole of CH₄ molecules is:_____ **Any help would be greatly appreciated!**
frozen [14]

Answer:

The bond dissociation energy to break 4 bonds in 1 mol of CH is 1644 kJ

Explanation:

Since there are 4 C-H bonds in CH₄, the bond dissociation energy of 1 mol of CH₄ is 4 × bond dissociation energy of one C-H bond.

From the table one mole is C-H bond requires 411 kJ, that is 411 kJ/mol. Therefore, 4 C-H bonds would require 4 × 411 kJ = 1644 kJ

So, the bond dissociation energy to break 4 bonds in 1 mol of CH₄ is 1644 kJ

5 0
2 years ago
A 0.1946 g piece of magnesium metal is burned in a constant-volume calorimeter that has a heat capacity for the bomb only of 134
Phoenix [80]

Answer:

The heat of combustion of magnesium metal is 24.76 kJ/gram

Explanation:

Step 1: Data given

Mass of magnesium sample = 0.1946 grams

Molar mass of magnesium = 24.3 g/mol

bomb calorimeter that has a heat capacity of 1349 J/°C

Mass of water = 500 grams

Temperature change = 1.40 °C

Step 2: Calculated heat released

Q = (1349 J/°C * 1.40 °C) + (500 grams * 4.184 J/g°C * 1.40 °C)

Q =4817.4 J = 4.82 kJ

Step 3: Calculate the heat given off by the burning Mg, in kJ/g

4817.4 J / 0.1946 grams = 24755.4 J/ gram = 24.76 kJ/ gram

The heat of combustion of magnesium metal is 24.76 kJ/gram

5 0
2 years ago
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