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juin [17]
1 year ago
14

A 0.1946 g piece of magnesium metal is burned in a constant-volume calorimeter that has a heat capacity for the bomb only of 134

9 J/°C. The calorimeter contains 5.00 x 102g of water and the temperature rise is 1.40°C. Calculate the heat of combustion of magnesium metal in kJ/g, given that thespecific heat of water is 4.184 J/g·°C.
Chemistry
1 answer:
Phoenix [80]1 year ago
5 0

Answer:

The heat of combustion of magnesium metal is 24.76 kJ/gram

Explanation:

Step 1: Data given

Mass of magnesium sample = 0.1946 grams

Molar mass of magnesium = 24.3 g/mol

bomb calorimeter that has a heat capacity of 1349 J/°C

Mass of water = 500 grams

Temperature change = 1.40 °C

Step 2: Calculated heat released

Q = (1349 J/°C * 1.40 °C) + (500 grams * 4.184 J/g°C * 1.40 °C)

Q =4817.4 J = 4.82 kJ

Step 3: Calculate the heat given off by the burning Mg, in kJ/g

4817.4 J / 0.1946 grams = 24755.4 J/ gram = 24.76 kJ/ gram

The heat of combustion of magnesium metal is 24.76 kJ/gram

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Mass of lead (II) chromate is 51 g. The molecular formula is PbCrO_{4} and its molar mass is 323.2 g/mol

Number of moles can be calculated using the following formula:

n=\frac{m}{M}

Here, m is mass and M is molar mass.

Putting the values,

n=\frac{(51 g}{323.1937 g/mol}=0.1578 mol

Therefore, number of moles of lead (II) chromate will be 0.1578 mol.

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1 year ago
What is the temperature change on a 75.0 gram sample of mercury if 480.0 cal of heat are added to it? The specific heat of mercu
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Answer:

\Delta T=194^oC

Explanation:

Hello,

In this case, in terms of the heat, mass, heat capacity and change in temperature, we can analyze thermal changes as:

Q=mCp\Delta T\\

In such a way, we compute the required change in temperature as shown below:

\Delta T=\frac{Q}{mCp}=\frac{480.0cal}{75.0g*0.033\frac{cal}{g^oC} }  \\\\\Delta T=194^oC

Such change in temperature is positive indicating an increase in the temperature as the involved heat is positive, in means that heat was added to increase the temperature.

Best regards.

6 0
1 year ago
. If one mole each of CH4, NH3, H2S, and CO2 is added to 1 liter of water in a flask (1 liter of water = 55.5 moles of H2O), how
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1 litre of water is = 55.5 moles of water.
water is H2O
so, in water:
moles of oxygen = 55.5
moles of hydrogen = 2 x 55.5 = 111

Now, 1 mole each of <span>CH4, NH3, H2S, and CO2 are added:
For CH4: 
moles of C = 1
moles of H = 4 x 1 = 4

For NH3:
moles of N = 1
moles of H = 3 x 1 = 3

For H2S:
moles of H = 2 x 1 = 2
</span>moles of S = 1
<span>
For CO2:
</span>moles of C = 1
moles of  = 2 x 1 = 2
<span>
Now, add the total moles of each atom:
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Carbon = 1+1 = 2
Sulfur = 1
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</span>
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2 years ago
Which of the following correctly shows the word equation for the formation of water from oxygen and hydrogen?
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A shows okay please mark it brainliest

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If the same amount of heat is supplied to samples of 10.0 g each of aluminum, iron, and copper all at 15.0 °c, which sample woul
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The formula that relates specific heat capacity and change in temperature is as follows:

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Since, the initial temperature is same for all the samples thus, Cu will reach the highest  temperature.

6 0
2 years ago
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