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timurjin [86]
2 years ago
13

Scientist in a lab are working with2 different types of mercury they know the different samples are different isotopes which pro

peetybof the isotopes must be different
Physics
1 answer:
Fudgin [204]2 years ago
6 0

Answer:

The atomic weight

Explanation:

<em>The property of isotopes that must be different is the </em><em>atomic weight</em><em>.</em>

<u>Isotopes are generally referred to as atoms of the same element with the same atomic number (proton number) but different neutron numbers.</u>

Since the atomic weight of an atom is the sum of proton and neutron, atomsof the same element with different number of neutrons will definitely have different atomic weight.

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Briana swings a ball on the end of a rope in a circle. The rope is 1.5 m long. The ball completes a full circle every 2.2 s. Wha
schepotkina [342]
The radius of the circular path is 1.5 m.

The circumference is then
1.5\ m*2\pi=3\pi\ m

The ball moves 3π m every 2.2 s, so the speed is
\frac{3\pi\ m}{2.2\ s}\approx 4.3\ m/s
9 0
2 years ago
Read 2 more answers
An elevator has a weight of 14,700 N and has an acceleration of –0.30 m/s2. The free-body diagram shows the forces acting on the
qwelly [4]

14250. I just took it

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2 years ago
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A stone falls from rest from the top of a cliff. A second stone is thrown downward from the same height 2.7 s later with an init
Darina [25.2K]

Answer:4.05 s

Explanation:

Given

First stone is drop from cliff and second stone is thrown with a speed of 52.92 m/s after 2.7 s

Both hit the ground at the same time

Let h be the height of cliff and it reaches after time t

h=\frac{gt^2}{2}

For second stone

h=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}---2

Equating 1 &2 we get

\frac{gt^2}{2}=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}

\frac{g}{2}\left ( t-t+2.7\right )\left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0

13.23\times \left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0

26.46t-35.721-52.92t+142.884=0

t=4.05 s

4 0
2 years ago
Two strings are respectively 1.00 m and 2.00 m long. Which of the following wavelengths, in meters, could represent harmonics pr
MrRissso [65]

Answer:

5) 4.00, 2.00, 1.0

Explanation:

wave equation is given as;

F₀ = V / λ

Where;

F₀ is the fundamental frequency = first harmonic

Length of the string for first harmonic is given as;

L₀ = (¹/₂) λ  

λ  = 2 L₀

when L₀ = 1

λ  = 2 x 1 = 2m

when L₀ = 2m

λ  = 2 x 2 = 4m

For First harmonic, the wavelength is 2m, 4m

For second harmonic;

L₁ = (²/₂)λ  

L₁ = λ

When L₁ = 1

λ  = 1 m

when L₁ = 2

λ  = 2 m

For second harmonic, the wavelength is 1m, 2m

Thus, the wavelength that could represent harmonics present on both strings is 4m, 2m, 1 m

6 0
2 years ago
What is the instantaneous velocity v of the particle at t=10.0s?
Alexeev081 [22]

Instantaneous velocity is defined at a specific value of time t. It can never be observed or measure. To know a velocity, one must know its distance and velocity. It is represented by the equation velocity is equal to delta distance over delta time. The problem above lacks data.

8 0
2 years ago
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