A woman is driving her truck with speed 45.0 mi/h on a horizontal stretch of road. (a) When the road is wet, the coefficient of
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Answer:
μ = 0.692
Explanation:
In order to solve this problem, we must make a free body diagram and include the respective forces acting on the body. Similarly, deduce the respective equations according to the conditions of the problem and the directions of the forces.
Attached is an image with the respective forces:
A summation of forces on the Y-axis is performed equal to zero, in order to determine the normal force N. this summation is equal to zero since there is no movement on the Y-axis.
Since the body moves at a constant speed, there is no acceleration so the sum of forces on the X-axis must be equal to zero.
The frictional force is defined as the product of the coefficient of friction by the normal force. In this way, we can calculate the coefficient of friction.
The process of solving this problem can be seen in the attached image.
Answer:
The final velocity of the first glider is 0.27 m/s in the same direction as the first glider
The final velocity of the second glider is 1.07 m/s in the same direction as the first glider.
0.010935 J
0.0858675 J
Explanation:
= Mass of first glider = 0.3 kg
= Mass of second glider = 0.15 kg
= Initial Velocity of first glider = 0.8 m/s
= Initial Velocity of second glider = 0 m/s
= Final Velocity of first glider
= Final Velocity of second glider
As momentum and Energy is conserved
From the two equations we get
The final velocity of the first glider is 0.27 m/s in the same direction as the first glider
The final velocity of the second glider is 1.07 m/s in the same direction as the first glider.
Kinetic energy is given by
Final kinetic energy of first glider is 0.010935 J
Final kinetic energy of second glider is 0.0858675 J