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2 years ago

12

The difference in the water levels of a beaker holding an upside-down buret containing a pocket of hydrogen gas is 23 cm H2O. Wh

at is the difference in pressure (pressure correction factor) between the atmospheric pressure and the pressure inside the buret? Express this in torr.

1 answer:

OleMash [197]2 years ago

3 0

Answer:

Pressure difference = 16.9 torr

Explanation:

The formula to be used since their is a difference in water level in the beaker and burette is;

Atmospheric pressure = pressure of gas in burette + pressure of water

Atmospheric pressure - gas pressure = pressure of water

Therefore, the difference between atmospheric pressure and gas pressure can be seen to be the pressure of the water

The pressure of water in mmHg = 23 cm H20 = 230 mmH2O

To convert to mmHg, we have to divide by 13.6 since mercury is 13.6 times heavier than water.

Pressure of water = 230 mmH2O * (1 mmHg/13.6 mmH20) = 16.9 mmHg

Since I mmHg = 1 torr, therefore,

Pressure difference = 16.9 torr

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b. chlorine

Explanation:

it has the highest atomic radius

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Morant Bay is 33 km south of Port Antonio a pigeon can fly at a speed of 1.2 m s what is the displacement of morant bay from Por

valkas [14]

Answer:

33km due south

Explanation:

Morant Bay is 33km south of Port Antonio;

Problem: displacement of Morant bay from Port Antonio;

Displacement is a vector quantity. It is the length of path between two position and the direction inclusive.

So, it has magnitude and must be specified with a direction.

Therefore, the displacement of Morant Bay from Port Antonio is 33km due south.

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An irregularly shaped solid which has a mass of 10.283g was placed in a graduated cylinder containing an inert liquid. The initi

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Liquid + Solid = 8.89 mL
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= 3.9 g/mL = 3.9 g / cm³

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2 years ago

A sixth grade teacher takes students on a field trip to the beach. One student finds several pebbles that have a rounded shape a

Fittoniya [83]

Answer:

C: The shape of the pebbles is a result of weathering and deposition

Explanation:

For the several pebbles to have a rounded shape and smooth to the touch, it will undergo weathering and deposition. This is because weathering involves breaking down of rocks and creating new sediments. This weathering could be either chemical weathering or physical weathering where Chemical weathering is the decomposition of rocks which are caused by chemical reactions and which result in formation of new compound while physical weathering is the breakdown of rocks into smaller pieces. On the other hand, deposition occurs when the agents of erosion such as wind or water deposit sediments from one spot to another which in turn changes the shape of the land.

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7 0

2 years ago

An unknown salt is either NaF, NaCl, or NaOCl. When 0.050 mol of the salt is dissolved in water to form 0.500 L of solution, the

victus00 [196]

<u>Answer:</u> The unknown salt is NaF

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of salt = 0.050 moles

Volume of solution = 0.500 L

Putting values in above equation, we get:

$\text{Molarity of salt}=\frac{0.050mol}{0.500L}\\\\\text{Molarity of salt}=0.1M$

To calculate the hydroxide ion concentration, we first calculate pOH of the solution, which is:

pH + pOH = 14

We are given:

pH = 8.08

$pOH=14-8.08=5.92$

To calculate pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

Putting values in above equation, we get:

$5.92=-\log[OH^-]$

$[OH^-]=10^{-5.92}=1.202\times 10^{-6}M$

The unknown salt given are formed by the combination of weak acid and strong acid which is NaOH

The chemical equation for the hydrolysis of $X^-$ ions follows:

$X^-(aq.)+H_2O(l)\rightleftharpoons HX(aq.)+OH^-(aq.);K_b$

<u>Initial:</u> 0.1

<u>At eqllm:</u> 0.1-x x x

Concentration of $OH^-=x=1.202\times 10^{-6}M$

The expression of $K_b$ for above equation follows:

$K_b=\frac{[OH^-][HX]}{[X^-]}$

Putting values in above expression, we get:

$K_b=\frac{(1.202\times 10^{-6})\times (1.202\times 10^{-6})}{(1-(1.202\times 10^{-6}))}\\\\K_b=1.445\times 10^{-11}M$

To calculate the acid dissociation constant for the given base dissociation constant, we use the equation:

$K_w=K_b\times K_a$

where,

$K_w$ = Ionic product of water = $10^{-14}$

$K_a$ = Acid dissociation constant

$K_b$ = Base dissociation constant = $1.445\times 10^{-11}$

Putting values in above equation, we get:

$10^{-14}=1.445\times 10^{-11}\times K_a\\\\K_a=\frac{10^{-14}}{1.445\times 10^{-11}}=6.92\times 10^{-4}$

We know that:

$K_a\text{ for HF}=6.8\times 10^{-6}$

$K_a\text{ for HCl}=1.3\times 10^{6}$

$K_a\text{ for HClO}=3.0\times 10^{-8}$

So, the calculated $K_a$ is approximately equal to the $K_a$ of HF

Hence, the unknown salt is NaF

6 0

2 years ago