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Schach [20]
2 years ago
8

A sphere of radius 0.03m has a point charge of q= 7.6 micro C located at it’s centre. Find the electric flux through it?

Physics
1 answer:
GalinKa [24]2 years ago
7 0

Answer:

The electric flux through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

Explanation:

Given

Radius,\ r = 0.03m\\Charge,\ q =7.6\µC

Required

Find the electric flux

Electric flux is calculated using the following formula;

Ф = q/ε

Where ε is the electric constant permitivitty

ε = 8.8542 * 10^{-12}

Substitute ε = 8.8542 * 10^{-12} and q =7.6\µC; The formula becomes

Ф = \frac{7.6\µC}{8.8542 * 10^{-12}}

Ф = \frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}

Ф = \frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}

Ф = \frac{7.6}{8.8542} *10^{12-6}}

Ф = 0.85834970974 *10^{12-6}}

Ф = 0.85834970974 *10^{6}}

Ф = 8.5834970974 *10^{5}}

Ф = 8.58 *10^{5} \frac{Nm^2}{C}

Hence, the electric flux through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

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Answer:

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A 6.0-ohm resistor that obeys Ohm’s Law is connected to a source of variable potential difference. When the applied voltage is d
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Init. A
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v = 1/3 m / s = 0.333 m / s

in the direction of the truck

Explanation:

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since the position is a vector we must add using vectors, we will assume that the displacement to the right is positive, the total displacement is

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2 years ago
You are given a vector in the xy plane that has a magnitude of 90.0 units and, a y component of -41.0 units. Assuming the x comp
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A standing wave of 603 Hz is produced on a string that is 1.33 m long and fixed on both ends. If the speed of the waves on this
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Answer:

4.

Explanation:

Given,

frequency of standing wave = 603 Hz

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n=\dfrac{l}{\frac{\lambda}{2}}

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n=\dfrac{2\times 1.33}{0.67}

n =3.97= 4.

Number of antinodes is equal to 4.

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