I think this is right I hope this is right for you
A locomotive moved 18.0 m [W] in a time of 6.00 s and stopped. After stopping, the locomotive moved 12.0 m [E] in 10.0 s. a. Det
1 answer:
Answer:
a) The distance travelled by the the locomotive is 30 meters, b) The final displacement of the locomotive is 6 meters westwards.
Explanation:
a) The distance travelled is the sum of magnitudes of distances covered by the train during its motion. That is to say:
The distance travelled by the the locomotive is 30 meters.
b) The displacement is the vectorial distance of the train with respect to a point of reference, since west and east are antiparallel to each other, calculations can be simplified to a scalar form. Let suppose that movement to the east is positive. The calculations are presented below:
The final displacement of the locomotive is 6 meters westwards.
You might be interested in
Answer:
From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases
Explanation:
I cannot find any attached photo, but we can proceed anyways theoretically.
The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point
i.e
But the force F
But the electric field intensity due to a point charge Q at a distance r meters away is given by
<em>From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases</em>
When air is blown into the open pipe,
L =
where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation
⇒λ=
Note here that n=1 is for fundamental, n=2 is first harmonic and so on..
⇒ third harmonic will be n=4
Given L=6m, n=4, solving for λ we get:
λ= =3m
Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:
c=f.λ Or f=
⇒f=
≈115 Hz