Question

Jack pulls a sled across a level field by exerting a force of 110 n at an angle of 30 with the ground. what are the parallel and perpendicular components, respectively, of this force with respect to the ground?

Answer 1

You are given an applied force of 110 n with an angle of 30° with the ground. Since the  force is not perpendicular or parallel to the sled then you will have two components. These components are in sine and cosine form.

for parallel component
x = rcosβ
x = 110cos30°
x = 95.26

for the perpendicular component
y = rsinβ
y = 110sin30°
y = 55

Answer 2

Explanation:

It is given that,

Force exerted on the sled, F = 110 N

The angle force makes with the ground is 30 degrees.

There are two components of force i.e. the parallel and perpendicular components. They are termed as $F_x\ and\ F_y$

Parallel component :

$F_x=F\ cos\theta$

$F_x=100\ cos(30)$

$F_x=86.6\ N$

Perpendicular component :

$F_y=F\ sin\theta$

$F_y=100\ sin(30)$

$F_y=50\ N$

So, the parallel and perpendicular components of this force with respect to the ground are 86.6 N and 50 N respectively. Hence, this is the required solution.