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Crank
2 years ago
7

Jack pulls a sled across a level field by exerting a force of 110 n at an angle of 30 with the ground. what are the parallel and

perpendicular components, respectively, of this force with respect to the ground?
Physics
2 answers:
Elina [12.6K]2 years ago
3 0
<span>You are given an applied force of 110 n with an angle of 30</span>°<span> with the ground. Since the  force is not perpendicular or parallel to the sled then you will have two components. These components are in sine and cosine form.

for parallel component
x = rcos</span>β
<span>x = 110cos30</span>°
<span>x = 95.26

for the perpendicular component
y = rsin</span>β
<span>y = 110sin30</span>°
<span>y = 55</span>
Soloha48 [4]2 years ago
3 0

Explanation:

It is given that,

Force exerted on the sled, F = 110 N

The angle force makes with the ground is 30 degrees.

There are two components of force i.e. the parallel and perpendicular components. They are termed as F_x\ and\ F_y

Parallel component :

F_x=F\ cos\theta

F_x=100\ cos(30)

F_x=86.6\ N

Perpendicular component :

F_y=F\ sin\theta

F_y=100\ sin(30)

F_y=50\ N

So, the parallel and perpendicular components of this force with respect to the ground are 86.6 N and 50 N respectively. Hence, this is the required solution.

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A hockey puck slides off the edge of a table with an initial velocity of 23.2 m/s and experiences no air resistance. The height
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15.1°

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Instead, the vertical velocity changes, due to the presence of the acceleration due to gravity:

v_y(t)= v_{y0} -gt (1)

where

v_{y0}=0 is the initial vertical velocity

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Since the hockey puck falls from a height of h=2.00 m, the time it needs to reach the ground is given by

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Substituting t into (1) we find the final vertical velocity

v_y = -(9.8 m/s^2)(0.64 s)=-6.3 m/s

where the negative sign means that the velocity is downward.

Now that we have both components of the velocity, we can calculate the angle with respect to the horizontal:

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6 0
2 years ago
A steel aircraft carrier is 370 m long when moving through the icy North Atlantic at a temperature of 2.0 °C. By how much does t
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Answer:

The carrier lengthen is 0.08436 m.

Explanation:

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Length = 370 m

Initial temperature = 2.0°C

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Using formula of change of temperature

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Using formula of length

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Put the value into the formula

\Delta L=1.2\times10^{-5}\times370\times19

\Delta L=0.08436\ m

Hence, The carrier lengthen is 0.08436 m.

8 0
2 years ago
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