Answer:
μ = 0.350
Explanation:
For the person to able to move the box, the force exerted by the person on the box must equal the force exerted by the box:
In this case, force can be calculated as a product of mass (m) by the acceleration of gravity (g) and the coefficient of static friction (μ):
Therefore, for the person to be able to push the box horizontally, the coefficient of static friction between the box and the floor should not be higher than 0.350.
Answer:
See the explanation below
Explanation:
To better understand this problem, a cylinder sketch is attached before and after the cut, we see that after the cut, the shape of this resembles that of a right triangle.
We can find, the centroid in the xy plane, knowing that the centroid for a triangle is located a third of its base.
In the z axis there is no displacement of the centroid.
Answer:
acceleration = -15.3g
Explanation:
given data
speed = 6.00 m/s.
thickness = 12
moves the entire = 12.0 cm
solution
we will use here equation that is
v² - u² = 2 × a × s ........................1
here v = 0 is the final velocity and u = 6.0 m/s is initial velocity and s= 0.12 m is the distance covered and a is the acceleration
so we put here value and get acceleration
a =
a =
a = -150 m/s² ( negative sign means it is a deceleration )
and
acceleration in units of g
a =
a = -15.3 g
Explanation:
Below is an attachment containing the solution.
