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1 year ago

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The graph of f(x) shown below resembles the graph of g(x)=x^3, but it has been vertically stretched. Which of the following coul

d be the equation of f(x)?

1 answer:

Deffense [45]1 year ago

4 0

Answer: it’s b

Step-by-step explanation:

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Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and t

Assoli18 [71]

Answer:

To determine the number of real number solutions of as system of equations in which one equation is linear and the other is quadratic

1) Given that there are two variables, x and y as an example, we make y the subject of the equation of the linear equation and substitute the the expression for y in x into the quadratic equation

We simplify and check the number of real roots with the quadratic formula, $x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}$ for quadratic equations the form 0 = a·x² - b·x + c

Where b² > 4·a·c there are two possible solutions and when b² = 4·a·c equation there is only one solution.

Step-by-step explanation:

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1 year ago

What is the difference of the polynomials?(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)A–6x4y – 2x3y2 + 9x2y3 – 3xy4 + y5B–6x4y

saul85 [17]

We have to calculate the difference of the given polynomials, we follows as:

$(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-(6x^{4}y-5x^{2}y^{3}-y^{5})$

After opening the brackets, the signs of all the terms changes as there is negative sign before the bracket.

= $(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-6x^{4}y+5x^{2}y^{3}+y^{5})$

Combining all the like terms, we get as

= $(-2x^{3}y^{2})+(4x^{2}y^{3}+5x^{2}y^{3})-3xy^{4}-6x^{4}y+y^{5}$

= $-2x^{3}y^{2}+9x^{2}y^{3}-3xy^{4}-6x^{4}y+y^{5}$

Option A is the correct answer.

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