Complete Question:
A beam of white light is incident on the surface of a diamond at an angle
, since the index of refraction depends on the light's wavelength, the different colors that comprise white light will spread out as they pass through the diamond. For example, the indices of refraction in diamond are
for red light and
for blue light. Thus, blue light and red light are refracted at different angles inside the diamond. The surrounding air has
.
Now consider θc, the angle at which the blue refracted ray hits the bottom surface of the diamond. If θc is larger than the critical angle θcrit, the light will not be refracted out into the air, but instead it will be totally internally reflected back into the diamond. Find θcrit. Express your answer in degrees to four significant figures.
Answer:

Explanation:
Only the blue refracted ray is related to the critical angle in this question


The relationship between the critical angle(
),
and
can be given as 

Answer:
Common Sense
Explanation:
The chick has probably seen other chicks get caught by the Hawk and knows not to go near, or saw a giant bird flying straight towards it and used common sense to identify it as danger and run away. Although if this is for a test or a grade or something, please do not use the answer, it is most likely incorrect. This is honestly my best answer.
Answer:
t₁ = 0.95 s
Explanation:
In this chaos we must use the definition of Newton's second law
F = m a = m dv / dt
dv = F dt / m
Let's replace and integrate, let's take the upward direction of the plane as positive, the force is positive
dv = ∫ (3 + 2t) dt / m
v = (3 t + 2 t²/ 2) /m
Let's evaluate between the lower limit t = 0 v = -6 ft / s (going down) to the upper limit t = t and v = 0
0 - (-6) = (3 (t- 0) + (t² -0)) / m
t² + 3t -6m = 0
Let's look for the mass
W = mg
m = W / g
m = 20/32
m = 0.625 slug
Let's solve the second degree equation
t² + 3t -3.75 = 0
t = (-3 ± √ (32 + 4 1 3.75)) / 2
t = (-3 ± 4,899) / 2
t₁ = 0.95 s
t₂ = -3.95 s
We take the positive time
Velocity = fλ
where f is frequency in Hz, and λ is wavelength in meters.
<span>2.04 * 10⁸ m/s = 5.09 * 10¹⁴ Hz * λ </span>
<span>(2.04 * 10⁸ m/s) / (5.09 * 10¹⁴ Hz ) = λ </span>
<span>4.007*10⁻⁷ m = λ </span>
<span>The wavelength of the yellow light = 4.007*10⁻⁷ m<span> </span></span>
<em>To determine the y component of velocity of a projectile </em><u><em>sine </em></u><em>operation is performed on the angle of launch.</em>
<u>Answer:</u> <em>sine</em>
<u>Explanation:</u>
Thus 
The initial velocity u can be resolved along two directions.
Along the X direction initial velocity = u cos θ
Along y direction initial velocity= u sin θ
From the equation of motion 
Thus velocity along x direction
=u cos θ
Velocity along y direction
= u sinθ -gt
Sign of g is negative.