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andriy [413]
2 years ago
8

What is the relationship between the sequence of DNA’s subcomponents and the properties of DNA? 1. The amino acid sequence along

a segment of DNA determines the three-dimensional shape of the protein that will be produced. 2. The deoxyribose sequence in a DNA molecule determines the complementary molecule that will form double stranded DNA. 3. The nitrogenous base sequence along a segment of DNA determines the amino acid sequence that will be produced. 4. The sequence of enzymes in a DNA molecule determines the direction in which DNA will be transcribed into mRNA.
Chemistry
1 answer:
wel2 years ago
7 0

Answer:

3.

Explanation:

There are four nitrogenous bases in a DNA including guanine (G), adenine (A), cytosine (C) and Thymine (T) and together they form the nitrogenous base sequence arranged in a specific order of three letters such as GAC and TAG to form a genetic code.

These nitrogenous base sequences forming genetic code are amino acid specific and determine the amino acid sequence in DNA. for example: CTT determines leucine and GTT determines valine.

Hence, the correct option is "3".

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When the reaction CO2(g) + H2(g) ⇄ H2O(g) + CO(g) is at equilibrium at 1800◦C, the equilibrium concentrations are found to be [C
UNO [17]

Answer:

The new molar concentration of CO at equilibrium will be  :[CO]=1.16 M.

Explanation:

Equilibrium concentration of all reactant and product:

[CO_2] = 0.24 M, [H_2] = 0.24 M, [H_2O] = 0.48 M, [CO] = 0.48 M

Equilibrium constant of the reaction :

K=\frac{[H_2O][CO]}{[CO_2][H_2]}=\frac{0.48 M\times 0.48 M}{0.24 M\times 0.24 M}

K = 4

CO_2(g) + H_2(g) \rightleftharpoons H_2O(g) + CO(g)

Concentration at eq'm:

0.24 M          0.24 M                 0.48 M            0.48 M

After addition of 0.34 moles per liter of CO_2 and H_2 are added.

(0.24+0.34) M    (0.24+0.34) M  (0.48+x)M         (0.48+x)M

Equilibrium constant of the reaction after addition of more carbon dioxide and water:

K=4=\frac{(0.48+x)M\times (0.48+x)M}{(0.24+0.34)\times (0.24+0.34) M}

4=\frac{(0.48+x)^2}{(0.24+0.34)^2}

Solving for x: x = 0.68

The new molar concentration of CO at equilibrium will be:

[CO]= (0.48+x)M = (0.48+0.68 )M = 1.16 M

3 0
2 years ago
In a first order reaction 40% of reactant gets converted into product in 30 minutes. What time would it require to convert 75% i
e-lub [12.9K]
56 minutes and 15 seconds I believe
5 0
2 years ago
Consider a 20.0 % (m/v) solution. how can this be written as a conversion factor?
White raven [17]
A conversion factor is a fraction or a ratio representing a relationship of two different measurement values. To write 20% m/v to a conversion factor, we need to remember that a percent is a value that represents the amount of a part per 100 units of the whole. M/v in the given value represents that the percentage is by mass per volume. So, to write it as a conversion factor, we do as follows:

20% m/v = 20 mass units / 100 volume units = 1 mass units / 5 volume units

Usually units of this are in g per L. So, it is equivalent to 1 g / 5 L
4 0
2 years ago
C2H5OH(aq) + MnO− 4 (aq) → Mn2+(aq) + CH3COOH(aq) of acetic acid from ethanol by the action of permanganate ion in acidic soluti
Andreas93 [3]

Answer :

Ethanol (C_2H_5OH) act as reducing agent.

The smallest possible integer coefficient of MnO_4^- in the combined balanced equation is, 4

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

C_2H_5OH(aq)+MnO_4^-(aq)\rightarrow CH_3COOH(aq)+Mn^{2+}(aq)

The oxidation-reduction half reaction will be :

Oxidation : C_2H_6O\rightarrow C_2H_4O_2

Reduction : MnO_4^-\rightarrow Mn^{2+}

  • Now balance oxygen atom on both side.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2

Reduction : MnO_4^-\rightarrow Mn^{2+}+4H_2O

  • Now balance hydrogen atom on both side.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^+

Reduction : MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2O

  • Now balance the charge.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^++4e^-

Reduction : MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O

In order to balance the electrons, we multiply the oxidation reaction by 5 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : 5C_2H_6O+5H_2O\rightarrow 5C_2H_4O_2+20H^++20e^-

Reduction : 4MnO_4^-+32H^++20e^-\rightarrow 4Mn^{2+}+16H_2O

The balanced chemical equation in acidic medium will be,

5C_2H_6O+4MnO_4^-+12H^+\rightarrow 5C_2H_4O_2+4Mn^{2+}+11H_2O

In the redox reaction ethanol act as reducing agent and permanganate ion act as an oxidizing agent.

4 0
2 years ago
A vessel contains 18.06*10^23 molecules of ammonia gas at 25°c. Calculate the number of hydrogen atoms present in the ammonia ga
velikii [3]

Answer:

Explanation:

<h2>Before you use log you have to multiply the answer of 8.66 mol by 6.02⋅1023 by 3 because the answer of 8.66 mol by 6.02⋅1023 gives you the number of ammonia molecules and in each molecules there are 3 hydrogen atoms present. </h2><h2> </h2><h2>So it is: </h2><h2> </h2><h2>8.66⋅6.02⋅1023=5.21332⋅1024 </h2><h2>5.21332⋅1024⋅3=1.563996⋅1025 </h2><h2>log(1.563996⋅1025)=25.19 </h2>

8 0
2 years ago
Read 2 more answers
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