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2 years ago

Chemists use activity series to determine whether which type of reaction will occur?

2 answers:

5 0

Single replacement reactions. For example copper is more reactive than silver. So a copper wire in a silver solution will cause the silver to become a metal again.

olga2289 [7]2 years ago

5 0

Chemists use activity series to determine whether A SINGLE REPLACEMENT reaction will occur.

Activity series refers to a series of metals that are arranged in order of reactivity starting from the highest to the lowest. The series is used essentially to determine the products that are formed from single displacement reactions. A metal that is higher in the activity series will always replace a metal that is lower in the series if rhe two of them exist in the same solution. This is because, a metal that is higher in the series will be more reactive than a metal that is below in activity series.

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Analyze and solve this partially completed galvanic cell puzzle. There are 4 electrodes each identified by a letter of the alpha

klasskru [66]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is $E_{cell}__{AC}} = 0.94$

Explanation:

From the question we are told that

the cell voltage for AD is $E_{cell}__{AD}} = 1.56V$

From the data give we can see that

$E_{cell}__{AD}} - E_{cell}__{BD}} = E_{cell}__{AB}}$

i.e $1.56 - 1.53 = 0.03$

In the same way we can say that

$E_{cell}__{AD}}-E_{cell}__{CD}} = E_{cell}__{AC}}$

=> $E_{cell}__{AC}}=1.56- 0.62$

$E_{cell}__{AC}} = 0.94$

5 0

2 years ago

What is net ionic equation borax hydrolysis?

deff fn [24]

The net ionic equation of borax hydrolysis would be:

Na2B4O7 + 7H2O-----------------> 2 NaOH + 4 H3BO3

Wherein 2 moles of sodium hydroxide and 4 moles of boric acid are produced by the hydrolysis.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

7 0

2 years ago

Simplify: (100 m)/(26 s)

podryga [215]

100m/26s=50m/13s

50m/13s=3.846m/s

4 0

2 years ago

Read 2 more answers

You have 49.8 g of O2 gas in a container with twice the volume as one with CO2 gas. The pressure and temperature of both contain

IrinaVladis [17]

Answer:

34.2 g is the mass of carbon dioxide gas one have in the container.

Explanation:

Moles of $O_2$ :-

Mass = 49.8 g

Molar mass of oxygen gas = 32 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{49.8\ g}{32\ g/mol}$

$Moles_{O_2}= 1.55625\ mol$

Since pressure and volume are constant, we can use the Avogadro's law as:-

$\frac {V_1}{n_1}=\frac {V_2}{n_2}$

Given ,

V₂ is twice the volume of V₁

V₂ = 2V₁

n₁ = ?

n₂ = 1.55625 mol

Using above equation as:

$\frac {V_1}{n_1}=\frac {V_2}{n_2}$

$\frac {V_1}{n_1}=\frac {2\times V_1}{1.55625}$

n₁ = 0.778125 moles

Moles of carbon dioxide = 0.778125 moles

Molar mass of $CO_2$ = 44.0 g/mol

Mass of $CO_2$ = Moles × Molar mass = 0.778125 × 44.0 g = 34.2 g

34.2 g is the mass of carbon dioxide gas one have in the container.

5 0

2 years ago

A gas cylinder filled with nitrogen at standard temperature and pressure has a mass of 37.289 g. The same container filled with

andrew-mc [135]

Answer:

Molar mass = 3.9236 g/mol ≅ 4 g/mol

This corresponds to Helium gas.

Explanation:

Let the moles of nitrogen gas = x moles

Moles of carbon dioxide = x moles ( As both are filled at same temperature and pressure conditions )

Given:

$Mass_{Container}+Mass_{Nitrogen\ gas}=37.289\ g$

Molar mass of nitrogen gas, $N_2$ = 28.014 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$x\ moles= \frac{Mass}{28.014\ g/mol}$

Mass of nitrogen gas = 28.014x g

So,

Let, $Mass_{Container}=y$

$y+28.014x=37.289$

Similarly,

$Mass_{Container}+Mass_{Carbon\ dioxide\ gas}=37.440\ g$

Molar mass of nitrogen gas, $CO_2$ = 44.01 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$x\ moles= \frac{Mass{44.01\ g/mol}$

Mass of nitrogen gas = 44.01x g

So,

$y+44.01x=37.440$

Solving the two equations, we get :

$Mass_{Container}=y=37.025\ g$

x = 0.00943 moles

Thus, Given:

$Mass_{Container}+Mass_{Unknown\ gas}=37.062\ g$

$37.025\ g+Mass_{Unknown\ gas}=37.062\ g$

Mass of the gas = 0.037 moles

Moles = 0.00943 moles

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.00943\ moles= \frac{0.037\ g}Molar mass}$

Molar mass = 3.9236 g/mol ≅ 4 g/mol

This corresponds to Helium gas.

7 0

2 years ago