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vlabodo [156]
2 years ago
10

The molar absorptivity of a compound at 500 nm wavelength is 252 M-1cm-1. Suppose one prepares a solution by dissolving 0.00140

moles of a solute in enough water to make a 500.0 mL solution. What would be the absorbance in a 3 .00 mm pathlength cell?
Chemistry
1 answer:
adell [148]2 years ago
5 0

Answer:

The absorbance of the solution is 0.21168.

Explanation:

Given that,

Wavelength = 500 nm

Molar absorptivity = 252 M⁻¹ cm⁻¹

Number of moles = 0.00140

Volume of solution = 500.0 mL

Length = 3.00 mm

We need to calculate the molar concentration

Using formula of the molar concentration

C=\dfrac{N}{V}

Where, N = number of moles

V = volume

Put the value into the formula

C=\dfrac{0.00140}{0.5000}

C=0.0028\ M

We need to calculate the absorbance of the solution

Using formula of absorbance

A=\epsilon C l

Put the value into the formula

A=252\times0.0028\times0.300

A=0.21168

Hence, The absorbance of the solution is 0.21168.

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Answer:

Explanation:

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Explanation:

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A slice of pizza contains 29 g of carbohydrate, 13 g of protein and an unknown amount of fat. if the pizza contains 280 kcal, ho
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When different macronutrients (e.g., carbohydrates) are metabolized, they yield different amounts of energy, commonly measured in kilocalories.

They are given by the following conversion factors:

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If the slice of pizza contains 29 g carbohydrates, that means there are 4 kcal/g × 29 g = 116 kcal from carbohydrates. It contains 13 g protein, so there are 4 kcal/g <span>× 13 g = 52 kcal from protein.

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2 years ago
Read 2 more answers
a.) The diameter of a uranium atom is 3.50 Å . Express the radius of a uranium atom in both meters and nanometers. b.) How many
Svetradugi [14.3K]

Answer:

Th answer to your question is:

a)  3.5 x10⁻¹⁰ meters; 0.35 nm

b) 6857142.86 atoms

c) Volume = 2.06 x 10⁻²³ cm³

Explanation:

a) data

Uranium atoms = 3.5A°

meters

           1 A° ----------------  1 x 10 ⁻¹⁰ m

         3.5A° ---------------  x

 x = 3.5(1 x10⁻¹⁰)/ 1 = 3.5 x10⁻¹⁰ meters

          1 A° ------------------ 0.1 nm

        3.5 A° ---------------- 0.35 nm

b) 2.4 mm

Divide 2,40 mm / uranium diameter

But, first convert 3,5A° to mm   = 3.5 x 10⁻⁷ mm

# of uranium atoms = 2.4 / 3.5 x 10⁻⁷ = 6857142.86

c) volume in cubic cm

Convert 3.5A° to cm  = 3.5 x 10⁻⁸

Volume = 4/3 πr³ = (4/3) (3.14)(1.7 x10⁻⁸)³

Volume = 2.06 x 10⁻²³ cm³

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Let's note that 1 pint = 473.1765 mL, so 11 pints should be 5204.9415 mL.

We make a proportion out of the word problem

(85 mg glucose/ 100 mL) times (1 g/ 1000 mg) = 4.4242 grams of glucose

5 0
2 years ago
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