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bezimeni [28]
2 years ago
4

If you hold a piece of copper wire in an open flame, which of the following will most likely happen?

Physics
1 answer:
Eduardwww [97]2 years ago
8 0

Answer:

The heat will travel through the wire to your hand.

Explanation:

Thats the one that makes the most sense.

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A charge of 4.9 x 10-11 C is to be stored on each plate of a parallel-plate capacitor having an area of 150 mm2 and a plate sepa
Triss [41]

Answer:2.53*10^-10F

Explanation:

C=£o£r*A/d

Where £ is the permitivity of a constant

£o= 8.85*10^-12f/m

£r=6.3

A=150mm^2=0.015m^2

d=3.3mm= 0.0033m

C=8.85*10^-12*6.3*0.015/0.0033

C=8.85*6.3*10^-12*0.015/0.0033

C=55.755*0.015^-12/0.003

C=8.36/3.3*10^-13+3

C=2.53*10^-10F

7 0
2 years ago
what is the acceleration of a bowling ball that starts at rest and moves 300m down the gutter in 22.4 sec
exis [7]
<span>Acceleration is the change in velocity divided by time taken. It has both magnitude and direction. In this problem, the change in velocity would first have to be calculated. Velocity is distance divided by time. Therefore, the velocity here would be 300 m divided by 22.4 seconds. This gives a velocity of 13.3928 m/s. Since acceleration is velocity divided by time, it would be 13.3928 divided by 22.4, giving a final solution of 0.598 m/s^2.</span>
7 0
2 years ago
A 500 kg motorcycle accelerates at a rate of 2 m/s .how much force was applied to the motorcycle?
Aleksandr [31]

Answer:

by using formula F=ma which is m stand for mass a stand for acceleration. so 500kg × 2 ms^-2

8 0
2 years ago
Read 2 more answers
Monochromatic light is incident on a grating that is 75 mm wide and ruled with 50,000 lines. the second-order maximum is seen at
DIA [1.3K]

Answer:

The wavelength of the incident light is \lambda = 400 nm

Explanation:

Given data

Distance between the sits

d = \frac{0.075}{50000}

d = 1.5 × 10^{-6} m

\theta = 32.5°

m = 2

We know that the wavelength of the incident light is given by

\lambda = \frac{d\sin \theta}{m}

Put all the value in above formula we get

\lambda = \frac{1.5 (\sin 32.5)}{2}×10^{-6}

\lambda = 4 × 10^{-7} m

\lambda = 400 nm

Therefore the wavelength of the incident light is \lambda = 400 nm

4 0
2 years ago
3. In 1989, Michel Menin of France walked on a tightrope suspended under a
Tamiku [17]

Answer: 80m

Explanation:

Distance of balloon to the ground is 3150m

Let the distance of Menin's pocket to the ground be x

Let the distance between Menin's pocket to the balloon be y

Hence, x=3150-y------1

Using the equation of motion,

V^2= U^s + 2gs--------2

U= initial speed is 0m/s

g is replaced with a since the acceleration is under gravity (g) and not straight line (a), hence g is taken as 10m/s

40m/s is contant since U (the coin is at rest is 0) hence V =40m/s

Slotting our values into equation 2

40^2= 0^2 + 2 * 10* (3150-y)

1600 = 0 + 63000 - 20y

1600 - 63000 = - 20y

-61400 = - 20y minus cancel out minus on both sides of the equation

61400 = 20y

Hence y = 61400/20

3070m

Hence, recall equation 1

x = 3150 - 3070

80m

I hope this solve the problem.

6 0
2 years ago
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