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2 years ago

Mechanical advantage of a second class lever is always greater than one why? give reason

Physics

1 answer:

malfutka [58]2 years ago

5 0

Answer:

It is <u><em>because the load is in between fulcrum and effort making a longer effort arm than the load arm resulting to multiplication of force and a mechanical advantage of greater than 1.</em></u>

Explanation:

The distance from the fulcrum to the effort is the effort arm where as the distance from the fulcrum to the load is the load arm.

The first class lever has a mechanical advantage that varies per the position of the load with respect to effort position from the fulcrum. They have the fulcrum at the middle. For example, a beam balance and a pliers. The formula to remember is FLE for easy categorization of the lever classes.

The second class lever , the load is at the middle.For example a wheel barrow and a bottle opener. In this class, the effort arm is longer than the load arm.The effort is force multiplication making the mechanical advantage to be greater than 1.

The third class of lever has effort in the middle.For example a spade or a knife.In this class effort arm is shorter than the load arm, causing change in direction of force. The effect is a mechanical advantage less than 1.

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A Honda Civic travels in a straight line along a road. The car’s distance x from a stop sign is given as a function of time t by

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a) Average velocity: 2.8 m/s

b) Average velocity: 5.2 m/s

c) Average velocity: 7.6 m/s

Explanation:

The position of the car as a function of time t is given by

$x(t)=\alpha t^2 - \beta t^3$

where

$\alpha = 1.50 m/s^2$

$\beta = 0.05 m/s^3$

The average velocity is given by the ratio between the displacement and the time taken:

$v=\frac{\Delta x}{\Delta t}$

The position at t = 0 is:

$x(0)=\alpha \cdot 0^2 - \beta \cdot 0^3 = 0$

The position at t = 2.00 s is:

$x(2)=\alpha \cdot 2^2 - \beta \cdot 2^3=5.6 m$

So the displacement is

$\Delta x = x(2)-x(0)=5.6-0=5.6 m$

The time interval is

$\Delta t = 2.0 s - 0 s = 2.0 s$

And so, the average velocity in this interval is

$v=\frac{5.6 m}{2.0 s}=2.8 m/s$

The position at t = 0 is:

$x(0)=\alpha \cdot 0^2 - \beta \cdot 0^3 = 0$

While the position at t = 4.00 s is:

$x(4)=\alpha \cdot 4^2 - \beta \cdot 4^3=20.8 m$

So the displacement is

$\Delta x = x(4)-x(0)=20.8-0=20.8 m$

The time interval is

$\Delta t = 4.0 - 0 = 4.0 s$

So the average velocity here is

$v=\frac{20.8}{4.0}=5.2 m/s$

The position at t = 2 s is:

$x(2)=\alpha \cdot 2^2 - \beta \cdot 2^3=5.6 m$

While the position at t = 4 s is:

$x(4)=\alpha \cdot 4^2 - \beta \cdot 4^3=20.8 m$

So the displacement is

$\Delta x = 20.8 - 5.6 = 15.2 m$

While the time interval is

$\Delta t = 4.0 - 2.0 = 2.0 s$

So the average velocity is

$v=\frac{15.2}{2.0}=7.6 m/s$

Learn more about average velocity:

brainly.com/question/8893949

brainly.com/question/5063905

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2 years ago

Stu wanted to calculate the resistance of a light bulb connected to a 4.0-V battery, with a resulting current of 0.5 A. He used

Margarita [4]

Answer:

The answer is not correct.

Explanation:

Stu's answer is not correct, the equation to use is known as the law of ohm. In which the voltage is defined as the product of the current by the resistance, then we will see this equation.

$V = I*R\\where:\\I = current [amp]\\R = resistance [ohm]\\V = voltage [volts]\\$

In order to find resistance, this term is found multiplying the current on the right side of the equation, therefore the current will be divided on the left side of the equation.

$R=\frac{V}{I} \\replacing:\\R=\frac{4}{0.5} \\R=8[ohms]$

That is the reason that the result found by Stu is not correct.

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2 years ago

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Since I'm assuming that its perfectly elastic, considering there's not enough information given, so I think that no energy is dissipated in the collision

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kobusy [5.1K]

Answer:

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Explanation:

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Pesticides are used from a very long time and repeated use of same pesticide allowed insects to get use to of it and evolve themselves in a way that they become resistant to these pesticide, so pesticide do not have any effect on insects.

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Answer:

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2 years ago

Mechanical advantage of a second class lever is always greater than one why? give reason​

Mechanical advantage of a second class lever is always greater than one why? give reason