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N76 [4]
2 years ago
15

A 1200-kg car pushes a 2100-kg truck that has a dead battery to the right. When the driver steps on the accelerator, the drive w

heels of the car push against the ground with a force of 4500 N. Which, if any, of the following gives a correct acceleration constraint for this problem? The variable ac is the acceleration of the car, and the variable t is the acceleration of the truck.
a. ac=at
b. ac=−at
c. ac=21001200at
d. ac=12002100at
e. There are no acceleration constraints for this problem.
Physics
1 answer:
worty [1.4K]2 years ago
8 0

Answer:

Option A: a_c = a_t

Explanation:

Let's denote the force acting on the car due to the truck as F_ct

Similarly, the force acting on the truck due to the car is denoted as F_tc.

Now, F_ct = m_c × a_c

Where;

m_c is mass of car

a_c is acceleration of car

Also, F_tc = m_t × a_t

Where;

m_c is mass of truck

a_c is acceleration of truck

Now, since the car is the one pushing the truck, from Newton's laws, we can say that they stick together and move in the same direction at the same acceleration.

Thus, the truck will move with an acceleration equal to that of the car pushing it.

Thus; a_c = a_t

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A huge (essentially infinite) horizontal nonconducting sheet 10.0 cm thick has charge uniformly spread over both faces. The uppe
Nonamiya [84]

Answer:

6.78 X 10³ N/C

Explanation:

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=  surface charge density / 2ε₀

Field will be perpendicular to the surface of the plate for both the charge density and direction of field will be same so they will add up.

Field due to charge density of +95.0 nC/m2

E₁ = 95 x 10⁻⁹ / 2 ε₀

Field due to charge density of -25.0 nC/m2

E₂ = 25 x 10⁻⁹ /  2ε₀

Total field

E = E₁ + E₂

= 95 x 10⁻⁹ / 2 ε₀ + 25 x 10⁻⁹ /  2ε₀

= 6.78 X 10³ N/C

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2 years ago
You drop a 6.0x10^-2 kg ball from height of 1.0m above hard flat surface. Ball strikes surface and energy decreases by 0.14J, th
harina [27]
If you drop a <span>6.0x10^-2 kg ball from height of 1.0m above hard flat surface, and a</span>fter the ball had bounce off the flat surface, the kinetic energy of the ball would be mgh - 0.14 = 0.45. 
3 0
2 years ago
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Fill in the blanks to complete each statement about weathering. Weathering is the breakdown of rocks into smaller particles call
nevsk [136]

Answer:

sediments

Explanation:

Weathering is the breakdown of rocks into smaller particles called:

                 sediments

Weathering is the physical disintegration and chemical decay of rocks into smaller fragments to produce sediments. The product of rock weathering is basically sediments. Some of the sediments can be transformed to form soils when they combine with organic matter, water and air.

Physical weathering is when rocks are physically broken into smaller pieces, but the minerals in  the rock remain the same.

             Physical weathering

Physical weathering is the disintegration of rocks into smaller bits without altering the chemical make up of the minerals. The goal of physical weathering is to expose rock surface to action of chemical weathering.

When a rock is broken down in a way that changes the mineral composition, it is called  chemical weathering

          chemical weathering

Chemical weathering is the decay of rocks by altering the minerals in a rock.

Hope this Helps! c:

8 1
2 years ago
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Joan and Mike's teacher show them a picture of an atom and ask them to identify it using the periodic table. Joan says the atom
zhenek [66]

Well we can't see the picture that the teacher has, and we have to figure out what's in the picture from some clues in the answer choices.  The picture seems to show an atom with 3 protons and 3 neutrons in the nucleus, and 3 electrons whizzing around the nucleus.

If that's what's in the picture, then Mike is correct (first choice), because the atomic number shows the number of protons in all atoms. There are 3 protons and the atomic number of lithium is 3.

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3 0
2 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
babymother [125]

Answer:

Explanation:

height of pole = 15 ft

height of man = 6 ft

Let the length of shadow is y .

According to the diagram

Let at any time the distance of man is x.

The two triangles are similar

\frac{y-x}{y}=\frac{6}{15}

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y=\frac{5}{3}x

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\frac{dy}{dt}=\frac{5}{3}\frac{dx}{dt}

As given, dx/dt = 4 ft/s

\frac{dy}{dt}=\frac{5}{3}\times 4

\frac{dy}{dt}=\frac{20}{3} ft/s

6 0
2 years ago
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